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2 years ago

One reason that driving lends itself to aggressive behavior is:

Engineering

2 answers:

Maurinko [17]2 years ago

5 0

Answer:

C. Drivers feel empowered by anonymity

Explanation:

Sorry for the late answer hope it helps you and others who need it.

STay Safe and healthy!

vlada-n [284]2 years ago

4 0

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96/64 reduced to its lowest term

Marina CMI [18]

Answer:

3/2

Explanation:

8 0

1 year ago

The specific volume of a system consisting of refrigerant-134a at 1.0 Mpa is 0.01 m /kg. The quality of the R-134a is: (a) 12.6%

Flura [38]

Answer:

option c is correct

47.2%

Explanation:

given data

consisting of refrigerant = 134 a

volume V = 0.01 m³/kg

pressure P = 1MPa = 1000 kPa

to find out

quality of the R 134a

solution

we will get here value of volume Vf and Vv from pressure table 60 kpa to 3 Mpa for 1 Mpa of R134 a

that is

Vf = 0.0008701 m³/kg

Vv = 0.0203 m³/kg

so we will apply here formula that is

quality = (V - Vf) / (Vv - Vf) ............1

put here value

quality = (0.01 - 0.0008701 ) / ( 0.0203 - 0.0008701 )

quality = 0.4698

so quality is 47 %

SO OPTION C IS CORRECT

4 0

2 years ago

River models are used to study many different types of flow situations. A certain small river has an average width and depth of

slavikrds [6]

Answer: 7ft x21 I’d be right but yes I am

Explanation: because it is Welty

4 0

2 years ago

For arwa and yeahahhahahhhhhhhhhhhhh

Setler79 [48]

Chicken nugget baby sauce

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2 years ago

Read 2 more answers

Lets assume, a represents the edge length (lattice constant) of a BCC unit cell and R represents the radius of the atom in the u

uranmaximum [27]

Answer:

$4\ R=\sqrt 3\ a$

Explanation:

Given that

Lattice constant = a

Radius of unit cell cell =R

Atom is in BCC structure.

In BCC unit cell (Body centered cube)

1.Eight atoms at eight corner of cube which have 1/8 part in each cube.

2.One complete atom at the body center of the cube

So the total number of atoms in the BCC

Z= 1/8 x 8 + 1 x 1

Z=2

In triangle ABD

$AB^2=AD^2+BD^2$

$AB^2=a^2+a^2$

$AB=\sqrt 2\ a$

In triangle ABC

$AC^2=AB^2+BC^2$

AC=4R

BC=a

$AB=\sqrt 2\ a$

$16R^2=2a^2+a^2$

$4\ R=\sqrt 3\ a$

So the relationship between lattice constant and radius of unit cell

$4\ R=\sqrt 3\ a$

7 0

2 years ago