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ollegr [7]
3 years ago
9

. Act 20 g Ca (M = 40g / mol) with H2SO4 diluted within 10 seconds. What will be the rate of hydrogen formation in mol / sec. pl

ease​
Chemistry
1 answer:
11111nata11111 [884]3 years ago
3 0

Answer:

Rate of hydrogen formation is 0.05 mole per second

Explanation:

Firstly, we write the equation of reaction.

When alkali earth metals react with dilute mineral acid, the reaction is vigorous with the production or evolution of hydrogen gas as a result of the displacement of the hydrogen from the acid by the metal. This is one of the basic reactions of mineral acids

Ca + H2SO4 ——> CaSO4 + H2

Looking at the reaction, 1 mole of calcium gave 1 mole of the hydrogen gas

What we do now is to calculate the number of moles of calcium produced by 20g of Ca

Mathematically;

number of moles = mass/atomic mass

number of moles of calcium is thus

20/40 = 0.5 moles

Now, if 1 mole of calcium produced 1 mole of the gas

Definitely, 0.5 mole of calcium will produce 0.5 mole of the gas

So the rate of gas formation would be 0.5/10 = 0.05 mole/second

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Answer:

  • <em>The volume of 14.0 g of nitrogen gas at STP is </em><u><em>11.2 liter.</em></u>

Explanation:

STP stands for standard pressure and temperature.

The International Institute of of Pure and Applied Chemistry, IUPAC changed the definition of standard temperature and pressure (STP) in 1982:

  •   Before the change, STP was defined as a temperature of 273.15 K and an absolute pressure of exactly 1 atm (101.325 kPa).

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Using the ideal gas equation of state, PV = nRT you can calculate the volume of one mole (n = 1)  of gas. With the former definition, the volume of a mol of gas at STP, rounded to 3 significant figures, was 22.4 liter. This is classical well known result.

With the later definition, the volume of a mol of gas at STP is 22.7 liter.

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<u>1) Convert 14.0 g of nitrogen gas to number of moles:</u>

  • n = mass in grams / molar mass
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  • Nitrogen gas is a diatomic molecule, so the molar mass of nitrogen gas = molar mass of N₂ = 14.0 × 2 g/mol = 28.0 g/mol
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<u>2) Set a proportion to calculate the volume of nitrogen gas:</u>

  • 22.4 liter / mol = x  / 0.500 mol
  • Solve for x: x = 0.500 mol × 22.4 liter / mol = 11.2 liter.

<u>Conclusion:</u> the volume of 14.0 g of nitrogen gas at STP is 11.2 liter.

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