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Alex Ar [27]
3 years ago
10

Which type of electromagnetic radiation is useful in communications technology

Physics
1 answer:
lisov135 [29]3 years ago
5 0

Radio, microwaves, infrared, and visible light are all used for communications.

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A conveyer belt moves a 40 kg box at a velocity of 2 m/s. What is the kinetic energy of the box while it is on the conveyor belt
ankoles [38]
Kinwtic energy = (40kg*2*2)/2=40*2=80J
4 0
3 years ago
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Which equation is correct according to Ohm’s law? Which equation is correct according to Ohm’s law? A.) V = IR B.) I = R/V C.) R
vodomira [7]

Answer:

V = IR

Explanation:

Required

Which equation represents ohm's law?

Literally, ohm's law implies that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R).

Mathematically, this can be represented as:

I\ \alpha\ \frac{V}{R}

Convert the expression to an equation

I\ =\ \frac{V}{R}

Multiply both sides by R to make V the subject

I\ * R\ =\ \frac{V}{R} * R

I\ * R\ =V

Reorder

V = I\ * R

V = IR

<em>Option (a) is correct; Others are not</em>

6 0
2 years ago
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For metalloids on the periodic table, how do the group number and the period number relate?
lapo4ka [179]
Im guessing it's (a) since the numbers go in chronological order and you read the periodic table left to right
3 0
3 years ago
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A speaker emits sound waves in all directions, and at a distance of 28 m from it the intensity level is 73 db. What is the total
Oduvanchick [21]

Answer:

P=0.197 Watt

Explanation:

Given That

B=73dB

Io= 1 * 10^-12

I=Io * 10^{\frac{B}{10} } \\I=2 * 10^{-5} Wm^{-2}  \\A=4 * pi * r^{2}\\ A=9852.03 m^{2}\\ Power= I * A\\P= 0.197 Watt

6 0
3 years ago
Consider the following three objects, each of the same mass and radius: (1) a solid sphere (2) a solid disk (3) a hoop All three
Vinil7 [7]

Answer:

The correct answer is

a) 1, 2, 3

Explanation:

In rolling down an inclined plane, the potential energy is Transferred to both linear and rotational kinetic energy thus

PE = KE or mgh = 1/2×m×v² + 1/2×I×ω²

The transformation equation fom potential to kinetic energy is =

m×g×h = \frac{1}{2} mv^{2} + \frac{1}{2} (\frac{2}{5} mr^{2} )(\frac{v}{r}) ^{2}

v_{Sphere} = \sqrt{\frac{10}{7} gh}

v_{Hoop} = \sqrt{gh}

v_{Disc}=\sqrt{\frac{4}{3} gh}

Therefore the order is with increasing rotational kinetic energy hence

the first is the sphere 1 followed by the disc 2 then the hoop 3

the correct order is a, 1, 2, 3

8 0
3 years ago
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