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3 years ago

Ummmm!! Can somebody please help me answer this question

Chemistry

2 answers:

nika2105 [10]3 years ago

8 0

The first one he discovered gravity when the apple fell on his head

Tems11 [23]3 years ago

3 0

Answer: is A because when the apple fell on him while he was thinking about the forces of nature he quickly studied it and sort of discovered it. That’s when he discovered gravity well it took him a while but he still did it. Hope it helped.

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The molecular ion is not visible in the mass spectrum of 2-chloro-2- methylpropane. At what m/z value would the molecular ion be

pochemuha

Answer: hello the complete question is attached below

Visibility of molecular ion = m/z value of 77

Explanation:

For The molecular ion to be visible, it has to be at an m/z value of 77 and this is because molecular ions will have an m/z ratio = molecular mass of given molecule in most cases but not always in all cases.

And the visibility is possible after the removal of CH₃ ion.

ii) Evidence in the mass spectrum that suggests peak at m/z = 77

attached below

5 0

3 years ago

WHAT IS IUPAC OF THIS

Oksanka [162]

Answer:

The Correct IUPAC name is H3C - CH (CH3) - CH (C2H5) - (CH2)2 - CH3 Class 11

Explanation:

ye thiss right it only show this for me like or star or comment if right all is good idc tell me if u got it

7 0

2 years ago

What about Kevlar makes it so strong? (1 point)

vfiekz [6]

I believe the answer is (B) as molten Kevlar when spun into fiber, its polymers have a crystalline arrangement.

Hope that helped!

7 0

2 years ago

The aromatic hydrocarbon cymene (C10H14) is found in nearly 100 spices and fragrances, including coriander, anise, and thyme. Th

andrezito [222]

Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

Explanation :

First we have to calculate the heat released by the combustion.

$q=c\times \Delta T$

where,

q = heat released = ?

$c$ = specific heat of calorimeter = $3.640kJ/^oC$

$\Delta T$ = change in temperature = $19.35^oC$

Now put all the given values in the above formula, we get:

$q=3.640kJ/^oC\times (19.35)^oC$

$q=70.43kJ$

Thus, the heat released by the combustion = 70.43 kJ

Now we have to calculate the molar enthalpy combustion.

$\Delta H=-\frac{q}{n}$

where,

$\Delta H$ = molar enthalpy combustion = ?

q = heat released = 70.43 kJ

n = number of moles cymene = $\frac{\text{Mass of cymene}}{\text{Molar mass of cymene}}=\frac{1.608g}{164.22g/mol}=0.009792mole$

$\Delta H=-\frac{70.43kJ}{0.009792mole}=-7193kJ/mole$

Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole

4 0

3 years ago

A sample of gas has a volume of 12.0 L and a pressure of 1.97 atm. If the pressure is increased to 3.40 atm, what is the new vol

sveticcg [70]

As far as I know, may be wrong :When pressure is multiplied by a number, the gas volume also gets multiplied by the same number. So, the answer can be found by doing: (3.4/1.97)(12), and the answer is about 20.71.

8 0

4 years ago