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Arisa [49]
3 years ago
8

Relacione el punto de ebullición del agua y la acetona (propanona), con la facilidad de a evaporación de estas sustancias (volat

ilidad), considerando las fuerzas intermoleculares.

Chemistry
1 answer:
Elden [556K]3 years ago
4 0

Answer:

Here's what I get  

Explanation:

1. Water

The O-H bond in water is highly polar.

It has about one-third ionic character.

The partially-positive H atoms and partially negative O atoms strongly attract each other  by hydrogen bonds.

It takes a large amount of energy to separate the water molecules from each other.

Thus, the boiling point of water is relatively high (100 °C).

2. Acetone

The C=O bond in acetone is much less polar.

It is less than 20 % ionic.

The dipole-dipole attractions in acetone are much weaker than the hydrogen bonds in water.

It takes much less energy to separate the acetone molecules from each other.

Thus, even though the molar mass of acetone is more than three times that of water, the boiling point of acetone is only 56 °C.

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Sophie [7]

Answer:

5.0 38 84.0 749.7 528.0 729.0 738.9 739.0

7 0
2 years ago
Differentiate between the three types of simple permanent tissues on the basis of their cell walls​
True [87]

Answer:

Parenchyma is the most simple and specialized tissue which is concerned mainly with the vegetative activities of the plant. The cells are isodiametric with well-developed intercellular spaces, vacuolated cytoplasm and cellulosic cell wall.

Collenchyma is the tissue of the primary body. The cells of the tissue contain protoplasm and are living without intercellular spaces. The cell wall articulate at the corners and are made up of cellulose, hemicellulose, and pectin.

Sclerenchyma is the thick-walled cell tissue. In the beginning, the cell is living and have protoplasm, but due to deposition of impermeable secondary board lignin, they become dead thick and hard.

5 0
3 years ago
At 150°C the decomposition of acetaldehyde CH3CHO to methane is a first order reaction. If the
Crank

The decomposition time : 7.69 min ≈ 7.7 min

<h3>Further explanation</h3>

Given

rate constant : 0.029/min

a concentration of  0.050 mol L  to a concentration of 0.040 mol L

Required

the decomposition time

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time

For first-order reaction :

[A]=[Ao]e^(-kt)

or

ln[A]=-kt+ln(A0)

Input the value :

ln(0.040)=-(0.029)t+ln(0.050)

-3.219 = -0.029t -2.996

-0.223 =-0.029t

t=7.69 minutes

4 0
3 years ago
The compound trimethylamine, (CH3)3N, is a weak base when dissolved in water. Write the Kb expression for the weak base equilibr
Zina [86]

Answer:

Kb = [OH⁻] . [C₃H₉NH⁺] / [ C₃H₉N ]

Explanation:

The equation for the reaction of trimethylamine when it is dissolved in water is:

C₃H₉N  +  H₂O ⇄ C₃H₉NH⁺ + OH⁻   Kb

1 mol of trimethylamine catches a proton from the water in order to produce trimethylamonium.

It is a base, because it give OH⁻ to the medium

Expression for Kb (Molar concentration)

Kb = [OH⁻] . [C₃H₉NH⁺] / [ C₃H₉N ]

7 0
3 years ago
Consider the following reaction: 2CH3OH ---&gt; 2CH4+O2 delta H= +252.8kJ. Calculate the amount of heat transferred when 22.0g o
nydimaria [60]
To calculate the amount of heat transferred when an amount of reactant is decomposed, we must look at the balanced reaction and its corresponding heat of reaction. In this case, we can see that 252.8 kJ of heat is transferred per 2 moles of CH3OH used. When 22 g of CH3OH is used, 86.9 kJ is absorbed. 
4 0
3 years ago
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