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Marizza181 [45]
3 years ago
5

Differentiate between thermoplastic and thermosetting plastic. Give two examples of each.

Chemistry
1 answer:
vaieri [72.5K]3 years ago
5 0

Answer:

though thermoset plastics and thermoplastics sound similar, they have very different properties and applications... the primary physical difference Is that thermoplastics can be remelted back into a liquid , whereas thermose plastics alwas remain in a permanent solid state

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3 0
3 years ago
Match the description with either a dehydration reaction or a hydrolysis reaction.
Gelneren [198K]

Answer:

1) Hydrolysis

2)Dehydration

3)Dehydration

4)Hydrolysis

Explanation:

Hydrolysis is the chemical breakdown of substances by water and depends on the chemistry, solubility, pH, and the oxidation–reduction (Eh or redox) potential of compound

<em>https://www.sciencedirect.com/topics/earth-and-planetary-sciences/hydrolysis</em>

With hydrolysis water will be a reactant, not a product, and is associated with breaking down substances. Hence 1 and 4 being a Hydrolysis reaction.

Dehydration on the other hand, is defined as :

In a dehydration reaction, either a hydroxyl group from one molecule combines with a hydrogen atom from the other molecule, or two hydrogen atoms from one molecule combine with an oxygen atom on the other molecule. In either case, water is released, and the two molecules are joined together.

https://www.albert.io/blog/dehydration-synthesis-ap-biology-crash-course/

Therefore it is associated with creating a bond of sorts, and water is a product, which is why 2 and 3 are dehydration.

Hope this helps!

6 0
3 years ago
For elements in the third row of the periodic table and beyond, the octet rule is often not obeyed. a friend of yours says this
Rom4ik [11]

The reason that some of the elements of period three and beyond are steady in spite of not sticking to the octet rule is due to the fact of possessing the tendency of forming large size, and a tendency of making more than four bonds. For example, sulfur, it belongs to period 3 and is big enough to hold six fluorine atoms as can be seen in the molecule SF₆, while the second period of an element like nitrogen may not be big to comprise 6 fluorine atoms.  

The existence of unoccupied d orbitals are accessible for bonding for period 3 elements and beyond, the size plays a prime function than the tendency to produce more bonds. Hence, the suggestion of the second friend is correct.  


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Answer:

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Explanation:

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