Answer:
Explanation:
Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point
So we know that
here we know that
so we have
Answer:
Explanation:
according to ohms law we know that
v=IR
given current =2 amps
given resistance =6Ω
so voltage is
v=2*6 =12 V
Parallel Circuits<span>The voltage drop is the same across each parallel branch.The sum of the current in each individual branch is equal to the current outside the branches.<span>The equivalent or overall resistance of the collection of resistors is given by the equation. 1/Req = 1/R1 + 1/R2 + 1/R3 ...</span></span>
Answer:
Fp = 36 N
Fq = 58 N
Explanation:
Let the left end be the reference end with string p closest to it.
Let CCW moments be positive
Sum moments about p to zero
1(9.8)[2 - 1] + Fq[6 - 2] - 5(9.8)[8/2 - 2] - 1.5(9.8)[5 - 2] - 2(9.8)[7 - 2] = 0
Fq[4] = 23.5(9.8)
Fq = 57.575 ≈ 58 N
Sum moments about q to zero
1(9.8)[6 - 1] - Fp[6 - 2] + 5(9.8)[6 - 8/2] + 1.5(9.8)[6 - 5] - 2(9.8)[7 - 6] = 0
Fp = 35.525 N
or
Sum vertical forces to zero
Fp + 57.575 - (9.8)(1 + 1.5 + 2 + 5) = 0
Fp = 35.525 ≈ 36 N
Answer:
If this explosion is occurring in a closed environment this 'rule' would be:
The conservation of momentum.
Explanation:
In a close system which means the experiment is isolated from the surrounding environment and therefore not allowed to interact with its external space will have the same amount of momentum at the end of the experiment as the beginning by the equation of p=mv, p is momentum, m is mass and v is velocity.
