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3 years ago

Propenoic acid is an unsaturated carboxylic acid. Describe how you could show

Chemistry

1 answer:

Anestetic [448]3 years ago

4 0

Answer:

Tests for unsaturation involves addition across the multiple bonds in the unsaturated compound.

Explanation:

In organic chemistry, we define an unsaturated compound as any compound that contains a double or triple bond. These multiple bonds are also known as pi bonds.

There are two major tests for unsaturation which shall both be discussed here.

The first test for unsaturation is by the use of bromine water. The unknown sample is passed through a solution of bromine water which normally appears reddish brown. The bromine water becomes decolorized due to addition of bromine across the multiple bond. This is a standard test for unsaturation.

Secondly, unsaturated compounds decoulourize a solution of potassium permanganate when passed through it. This alone can not be used as a distinctive test for unsaturation.

Propenoic acid will give a positive test to the both reagents showing that it contains multiple bonds, in this particular instance, a double bond.

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HELP. Answer as much as possible. Thnx.

blondinia [14]

Answer:4

Explanation:

6 0

3 years ago

If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.

kicyunya [14]

Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

$CH_{3}COOH \ \textless \ ---\ \textgreater \ H^{+} + CH_{3}COO^{-}$

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> $[H^{+}]$ = $10^{-2.88}$ = 0.001 $moldm^{-3}$

The change in Concentration Δ $[CH_{3}COOH]$ = 0.001 $moldm^{-3}$

  CH3COOH H+ CH3COOH
Initial   $moldm^{-3}$      $x$ 0 0

Change $moldm^{-3}$ -0.001 +0.001 +0.001

Equilibrium $moldm^{-3}$ $x$ - 0.001 0.001 0.001


Since the $k_{a}$ value is so small, the assumption
$[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium}$ can be made.

$k_{a} = [tex]= 1.8*10^{-5} = \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} = \frac{0.001^{2}}{x}$

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps!

8 0

3 years ago

What is the net ionic equation for the reaction that occurs when aqueous copper(II) sulfate is added to excess 6-molar ammonia?a

Karolina [17]

Answer:

c. 2NH₃ + 2H₂O + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺

Explanation:

A net ionic equation is a chemical equation that list only the species that are involved in the reaction.

The reaction of ammonia with copper(II) sulfate CuSO₄ in water is:

2NH₃ + 2H₂O + CuSO₄ → Cu(OH)₂(s) + 2NH₄⁺ + SO₄²⁻

In an ionic equation, salts are written as ions, that means CuSO₄ must be written as Cu²⁺ + SO₄²⁻. That is:

2NH₃ + 2H₂O + Cu²⁺ + SO₄²⁻ → Cu(OH)₂(s) + 2NH₄⁺ + SO₄²⁻

As in a net ionic equation you must list only the species involved in the reaction (The underlined species don't react), the net ionic equation is:

c. 2NH₃ + 2H₂O + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺

I hope it helps!

7 0

3 years ago

What is the Pauli Exclusion Principle?

Fiesta28 [93]

Answer:

the answer is A An atomic orbital can only hold a maximum of 2 electrons, each with opposite spins

Explanation:

3 0

3 years ago

As a chlorine atom becomes a negative ion, the atom blanks an electron

Andrew [12]

Answer: increases by

As a chlorine atom becomes a negative ion, the atom "increases by" an electron

Explanation:

Chlorine atom has an atomic number of 17, and an electronic configuration of 1s2, 2s2 2p6, 3s2 3p5 showing 7 valence electrons in its outermost shell.

Hence, it receives a single electron to achieve a stable octet structure with electronic configuration of

1s2, 2s2 2p6, 3s2 3p6. Therefore, Cl- is a univalent negative ion with 8 valence electrons in its outermost shell. The increase is shown below

Cl + e- --> Cl-

Thus, as a chlorine atom becomes a negative ion, the atom "increases by" an electron

7 0

3 years ago