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anyanavicka [17]

4 years ago

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Car insurance incentives and discounts are available depending on _____. A. school attendance and driver skill B. vehicle type a

nd driver family size C. location and driver employment status D. location, vehicle type, and driving habits

2 answers:

borishaifa [10]4 years ago

7 0

Answer:D. Location, vehicle type, and driving habits

kozerog [31]4 years ago

5 0

D. Location, vehicle type, and driving habits.

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Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these d

Tems11 [23]

Complete Question

Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these devises are available for weekend warriors who want to play with their chain saws. Let us model the illustrated tongs as a planar mechanism that carries a log of weight 210 N. Given the following dimensions: 35 mm 10 mm 40 mm 230 mm 85 mm 45 mm 10 mm 35 mm 345 mm determine the force in N and moment in Nm that our worker exerts on the tongs. Also determine the pinching force magnitude in N that the tongs exert on the log; i.e. determine the horizontal force that the tong's teeth exert on the log. Assume the point E is centered between the tong's teeth.

The diagram for this question is shown on the first uploaded image

Answer:

The force P is $P= 210 N$

and the moment M is $M = -48.3N \cdot m$

The horizontal force that the tong teeth exerts is $F_T =89.67N$

Explanation:

First let denote the dimension to corresponding to the diagram

$a=35mm , b= 10mm, c= 40mm, d= 230mm, e= 85mm,f= 45mm,\\g= 10mm,h=35mm,i=345mm.$

Next looking at the diagram let us consider the vertical direction

At equilibrium

$\sum F_{vertical} =0$

This mean that

$P+ W = 0$

Since they are acting in opposite direction the equation becomes

$P - W = 0$

=> $P= W$

=> $P= 210 N$

At Equilibrium Moment about F gives

$\sum M_f = 0$

=> $F_T * (e +f + g+ h+ i) - F_T * (e+ f+g+ h+i) - W *d -M =0$

=> $M = -W *d$

=> $M = -210 * 0.230$

=> $M = -48.3N \cdot m$

Here $F_T$ is the horizontal force that the tong teeth exerts

Now let consider the part BAF of the system as shown on the second uploaded image

Now the angle $\theta$ is mathematically given as

$tan \theta = \frac{g+h}{a}$

=> $\theta = arctan \frac{g+h}{a}$

$= arctan (\frac{10+35}{35} )$

$=52.125^o$

Now at equilibrium the moment about A is

$\sum M_A = 0$

=> $P * (c+d) +M + F_{BC} cos \theta *f+F_{BC}sin\theta *(a+b) =0$

$210 * (0.040 + 0.230)-48.3+F_{BC} cos (52.125^o)*0.045+ F_{BC}sin(52.125^o)$ $* (0.035 +0.010) =0$

=> $10.29 +F_{BC} (0.02763+0.03552) =0$

=> $F_{BC} =\frac{10.29}{0.06315}$

=> $F_{BC} = - 162.925 N$

Looking at the forces acting on the teeth as shown on the third uploaded image

At Equilibrium the moment about D is

$\sum M_D = 0$

=> $\frac{W}{2} *d - F_T *(i+h) -F_{BC} cos \theta *h -F_{BC} sin \theta * (b+c) =0$

=> $\frac{210}{2} * 0.230 -F_T (0.345 +0.035) - (-162.925)cos(52.125^o) *0.035\\-(-162.925)sin(52.125^o)(0.010 +0.040) =0$

=> $34.081 = F_T(0.345 +0.035)$

=> $F_T =89.67N$

7 0

4 years ago

Admission to an aquarium is $14 per person. There is also an IMAX theatre in the building, which charges $8 per ticket for a 3D

adoni [48]

Answer:

x=14a+8b+16.5c

Explanation:

x=total cost

a=number of people in just aquarium

b=number of people in just IMAX

c=number of people in both

c=(14+8)×0.75=22×0.75=16.5

8 0

3 years ago

Dos capacitores de placas paralelas, idénticos, pero con la excepción de que uno tiene el doble de separación entre sus placas q

Charra [1.4K]

Las características de la capacitancia permiten encontrar los resultados para las diferentes preguntas

1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mayor densidad de carga

Los capacitores son sistema que sirve para acumular carga, esa formado por placas conductoras separadas una distancia pequeña, la capacitancia es

$C = \frac{Q}{DV} = \frac{\epsilon_o A}{d}$

Donde Q es a carga, ΔV la diferencia de potencial, A el area y d la separación de las placas.

Busquemos las respuestas para las diferentes preguntas:

1) Cual tiene mayor campo eléctrico.

El potencial y el campo eléctrico están relacionados

ΔV = - E d

E = - $\frac{\Delta V}{d}$

Indican que un capacitor tiene el doble de separación de las placas que el otro

Capacitor 1

E = $- \frac{\Delta V}{d_1}$

Capacitor 2

d₂ = 2 d₁

E₂ = $- \frac{\Delta V}{2d_1}$

E₂= ½ E₁

Por lo tanto el capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) Cual tiene mas carga

Busquemos la carga para cada capacitor

Q = ε₀ $\frac{A \Delta V}{d}$

Capacitor 1

Q₁ = (ε₀ A ΔV) $\frac{1}{d_1}$

Capacitor 2

Q₂ = (ε₀ A Δv) $\frac{1}{2d_1}$

Q₂ = Q₁/2

El capacitor con menor distancia tiene mayor carga

3) Cual tiene mayor densidad de energía

La densidad de energía en un capacitor esta dada por

$u_E$ = ½ ε₀ E²

calculamos para cada capacitor

Capacitor 1

$u_{E\ 1}$ = ½ ε₀ E₁²

Capacitor 2

$u_{E 2}$ = ½ ε₀ (E₁/2)²

por lo cual el capacitor con menor distancia tiene mas densidad de carga

En conclusión con lass característica de capacitancia podemos encontrar los resultados para las diferentes preguntas

1) El capacitor con menor distancia entre las placas tiene mayor campo eléctrico.

2) El capacitor con menor distancia tiene mayor carga

3) El capacitor con menor distancia tiene mas densidad de carga

Aprender mas aquí: brainly.com/question/22813371

7 0

3 years ago

Solved this question??????????????????

pogonyaev

I do not know!!!!!!!!

5 0

3 years ago

The Imager for Mars Pathfinder (IMP) is an imaging system. It has two camera channels. Each channel has color capability. This i

Crank

I believe it’s E. Not completely shure though

5 0

3 years ago