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3 years ago

HELP ASAP!!! 100 points!!!!!!!!!

Physics

2 answers:

Zepler [3.9K]3 years ago

6 0

Answer:

Shown from explanation.

Explanation:

The resonant frequency is related by the formula;

Fo= 1/2π√(K/M)

Where Fo is resonant frequency

M is mass

K is the spring constant

From the expression above;

When K is increased frequency would increases since frequency is directly proportional to spring constant.

Similarly when the mass is increased the frequency decreases since frequency is inversely proportional to the mass.

Amplitude is a property of a wave and so the frequency stays same.

Ira Lisetskai [31]3 years ago

5 0

Answer:

Hi!

So, this is what you need to do.

Fo = 1/2 π √(K/M)

The m = mass (in case you didn't know)

Explanation:

That should help you with your answer :)

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Factors that affect the light intensity received from a source

Roman55 [17]

Light intensity and distance is interrelated. When the distance changes, the intensity of light changes. This relationship is called inverse-square relationship. The inverse-square relationship refers to the fact that when distance changes, light intensity also changes: inverse because when distance decreases, light density increases and when distance increases, the latter decreases; square refers to the fact that light intensity and distance is not a one-to-one relationship.

6 0

3 years ago

Calcular la energía cinética de un Coyote de 30 kg que corre tras su presa con una velocidad de 65 km/h

Mumz [18]

Respuesta:

4.9 × 10³ J

Explicación:

Paso 1: Información provista

Masa del coyote (m): 30 kg

Velocidad del coyote (v): 65 km/h

Paso 2: Convertir la velocidad del coyote de km/h a m/s

Vamos a usar los siguientes factores de conversion:

1 km = 1000 m

1 h = 3600 s

65 km/h × (1000 m/1 km) × (1 h/3600 s) = 18 m/s

Paso 3: Calcular la energía cinética del coyote (K)

Usarémos la siguiente fórmula.

K = 1/2 × m × v²

K = 1/2 × 30 kg × (18 m/s)² = 4.9 × 10³ J

6 0

3 years ago

As the radius of the Gaussian surface increases, the magnitude of the electric field at the surface does which of the followingI

marshall27 [118]

Answer:

Decreases

Explanation:

Gauss's law states that the flux of the electric field through a closed surface is equal to the quotient between the charge inside that surface divided by the permittivity of free space:

$\int\limits {E\cdot dS} \,=\frac{Q_{enc}}{\epsilon_0}\\E=\frac{Q_{enc}}{A \epsilon_0}$

Therefore, the magnitude of the electric field is inversely proportional to the area, the area is directly proportional to the radius. So, as the radius of the Gaussian surface increases, the magnitude of the electric field at the surface decreases.

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3 years ago

Plzzz help with the question below!

KatRina [158]

The answer is place.

7 0

3 years ago

Define resistance of a conductor. State the factors on which resistance of a conductor depends.

e-lub [12.9K]

<h3>Answer:</h3>

1. Resistance is the opposition offered in a path of flow of current by the atoms or molecules of the conductor.

Factors on which resistance of a conductor depends are: