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12345 [234]
3 years ago
12

A liquid mixture in which particles can be seen and easily separated by settling or filtration is a_____?

Chemistry
2 answers:
damaskus [11]3 years ago
7 0

Answer:

A suspension

Explanation:

valentinak56 [21]3 years ago
3 0

Answer:

Explanation: A solution is a liquid mixture where it's not possible to identify the substances on which only seen it. The solvent is the substance that is more present in a solution, which dissolves the others, which are called the solutes.

Explanation:

google hope this helps you

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Which of the following molecules has correctly labeled bond dipoles?
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The bond dipole moment<span> uses the idea of </span>electric dipole moment<span> to measure the </span>polarity<span> of a chemical bond within a </span>molecule<span>. It occurs whenever there is a separation of positive and negative charges. In the diagram above, option B exhibited a bond dipole moment. I hope this helps.</span>
8 0
3 years ago
How will vinegar slow down the break down of an apple?
Gennadij [26K]

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3 years ago
How many moles in 2.33E25 molecules of NO?
Sindrei [870]

Answer:

0.0258 mol <em>Answer</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

6 0
3 years ago
The enthalpy change for converting 1.00 mol of ice at -50.0°c to water at 70.0°c is __________ kj. the specific heats of ice, wa
kogti [31]
First, calculate for the amount of heat used up for increasing the temperature of ice.

      H = mcpdT
       H = (18 g)*(2.09 J/g-K)(50 K) = 1881 J

Then, solve for the heat needed to convert the phase of water.
    H = (1 mol)(6.01 kJ/mol) = 6.01 kJ = 6010 J

Then, solve for the heat needed to increase again the temperature of water.
    H = (18 g)(4.18 J/gK)(70 k)
    H = 5266.8 J

The total value is equal to 13157.8 J

Answer: 13157.8 J
8 0
4 years ago
Given pH = 8.55 Find: [H3O+] and [OH-] Is this acidic, basic or neutral?
Firlakuza [10]

Answer:

Explanation:

The given pH = 8.55

Unknown:

[H₃O⁺] = ?

[OH⁻] = ?

In order to find these unknowns we must first establish some relationship.

                      pH = -log[H₃O⁺]

                   8.55 = -log[H₃O⁺]

                    [H₃O⁺] = inverse log₁₀(-8.55) = 2.82 x 10⁻⁹moldm⁻³

To find the [OH⁻],

                     pH + pOH = 14

                               pOH = 14 - pH = 14 - 8.55

                                pOH = 5.45

              pOH = -log[OH⁻]

               [OH⁻] = inverse log₁₀ (-5.45) = 3.55 x 10⁻⁶moldm⁻³

The solution is basic because it has more concentration of OH⁻ ions compared to H⁺ ions.

7 0
4 years ago
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