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Masja [62]
4 years ago
12

in a hypothetical element ,two energy levels are separated by an energy of 282kj mol-1 . what wavelength of light (in nma) is ev

olved for an electron to change between these two levels?​
Chemistry
1 answer:
Tom [10]4 years ago
6 0

Answer:

7.05 × 10⁻²² nm

Explanation:

Step 1: Given and required data

  • Energy evolved when a mole of electrons changes between the 2 levels (E): 282 kJ
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s
  • Speed of light (c): 3.00 × 10⁸ m/s

Step 2: Calculate the wavelength (λ) of the light evolved

We will use Planck-Einstein's relation.

E = h × c/λ

λ = h × c/E

λ = (6.63 × 10⁻³⁴ J.s) × (3.00 × 10⁸ m/s)/(282 × 10³ J) = 7.05 × 10⁻³¹ m

We will convert λ to nm using the conversion factor 1 m = 10⁹ nm.

7.05 × 10⁻³¹ m × 10⁹ nm/1 m = 7.05 × 10⁻²² nm

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Answer:

The precipitate is CuS.

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Explanation:

<u>Step 1: </u>Data given

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Ksp (FeS) = 6.3 × 10-18

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Calculate the minimum of amount needed to form precipitates:

Q=Ksp

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<u>For Iron</u>  we have: Ksp=[Fe2+]*[S2-]

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CuS will form precipitates before FeS., because only 3.61*10^-35 M Sulfur Ions are needed for CuS. For FeS we need 1.43*10^-16 M Sulfur Ions which is much larger.

The precipitate is CuS.

Sulfide will precipitate at  [S2-]= 3.61*10^-35 M

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c

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</span>Chemical reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.
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n(CaCO₃) = 10 g ÷ 100 g/mol.
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From chemical reaction: n(CaCO₃) : n(CO₂) = 1 : 1.
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