Answer:
30 m/s
Explanation:
Applying,
v = u+at................ Equation 1
Where v = final speed of the ball, u = initial speed of the ball, a = acceleration, t = time.
From the question,
Given: u = 0 m/s (stationary), a = 600 m/s², t = 0.05 s
Substitute these values into equation 5
v = 0+(600×0.05)
v = 30 m/s
Hence the speed at which the ball leaves the player's boot is 30 m/s
Answer:
Explanation:
The loss of gravitational potential energy must be equal to the gain of kinetic energy since there are no other interactions at play (no friction, etc).
We know that the change of potential energy will be written as , where <em>h</em> is the difference between the different heights.
We know that the change of kinetic energy will be written as , where <em>v</em> is the final velocity and we have assumed it departs from rest.
We then have:
We transform km/h to m/s by multiplying by the conversion factors (which are equal to 1, so don't alter the result):
So for our values we have:
to three significant figures.
Answer:
If it says in your own words you need to be the one to answer it!! :):):)
Explanation:
Answer:
2.8 seconds
Explanation:
First let us write out the formula relating the period(T),mass(m) and spring constant(k)
let assume
hence w can write the formula as
if we vary k, we arrive at
Now if the mass was doubled,
we arrive at
Since
Answer:
270000 round into 2 significant figures
= 2.7 × 10⁵
Thus, 2 and 7 are significant figures.
270000 round into 3 significant figures
= 2.70 × 10⁵
Thus, 2, 7 and 0 are significant figures.
<u>-</u><u>TheUnknownScientist</u>