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AVprozaik [17]
3 years ago
12

1. A diode laser has a band gap of eV0, where V0 is a voltage. The laser has an efficiency of 30%, meaning 30% of the power inpu

t is converted to laser light output. We run an electrical current I through the diode, where I is in amps.a. What is the wavelength of the photons produced by the laser
Engineering
1 answer:
Savatey [412]3 years ago
4 0

Answer:

Hence wavelength of the photons produced by the laser is

\frac{hc}{eV_0}

Explanation:

Given

Efficiency of laser - 30%

As we know

eV_0 = \frac{hc}{\Lambda}

h = plank's constant

c = speed of light

eV0 = band gap

Hence wavelength of the photons produced by the laser is

\Lambda= \frac{hc}{eV_0}

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Explanation:

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3 years ago
For the given network, if R = 0.8 [Ω], the natural response of i in(t) is:
11111nata11111 [884]

Answer:

Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56 A

Explanation:

In physics, the determination of the term " natural response" simply means that we want to know what happens in a circuit when the value of t = 0, that is to say after the circuit has been disconnected. Hence, the value of the voltage and the current can then be determined or Calculated;

For the the natural response of i in(t) we will be using the formula below;

I(t) = Vo × t/ R = Vo/R × e^-t/h.

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Hence, we will have;

Vin(t) = 0.8 × e^-t/1.56.

Iin(t) =1.3 × (-0.8/1.56) e^-t/1.56

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