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2 years ago

When NH3(aq) is added to Cu2 (aq), a precipitate initially forms. Its formula is:

1 answer:

3 0

It’s B the cu looses its 2 and passes it to the NH3 that needs a bracket to separate them. The NH3 doesn’t loose its 3 because it’s already a compound!
Hope this helps!

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Which of the following is not a magnetic material A cobalt B iron C nickel D plastic E steel

pentagon [3]

Answer:

<h2>D. plastic</h2>

$\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}$

6 0

2 years ago

A sample of aluminum, which has a specific heat capacity of 0.897·J·g−1°C^−1 , is put into a calorimeter (see sketch at right) t

Tcecarenko [31]

Answer: The mass of aluminium sample is 55.4 gram

Explanation:

$Q_{absorbed}=Q_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$

where,

$m_1$ = mass of aluminium = ?

$m_2$ = mass of water = 300.0 g

$T_{final}$ = final temperature = $23.8^0C$

$T_1$ = temperature of aluminium = $94.5^oC$

$T_2$ = temperature of water = $21.0^oC$

$c_1$ = specific heat of aluminium = $0.897J/g^0C$

$c_2$ = specific heat of water = $4.184J/g^0C$

Now put all the given values in equation (1), we get

$-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]$

$-[m_1\times 0.897\times (23.8-94.5)^0C]=[300.0g\times 4.184\times (23.8-21.0)]$

$m_1=55.4g$

Therefore, the mass of aluminium sample is 55.4 gram

8 0

2 years ago

Please Help!!!

Darya [45]

How many grams of glucose is dissolved in 2.88% glucose solution if 1944 grams of water is used???? The answer is C. 56 grams

8 0

2 years ago

Which pair of elements do you expect to be most similar in their chemical properties?

Dmitry [639]

Isotopes of carbon or any element

7 0

2 years ago

Suppose that NaCl is added to hexane (C6H14) instead of water. Which of the following intermolecular forces will exist in the sy

svet-max [94.6K]

Answer:

Ion-ion force between Na+ and Cl− ions

London dispersion force between two hexane molecules

Explanation:

"Ion-dipole force between Na+ ions and a hexane molecule " does not exist since hexane has only non-polar bonds and therefore no dipole.

"Ion-ion force between Na+ and Cl− ions " exists since both are ions.

"Dipole-dipole force between two hexane molecules " does not exist since hexane molecules do not have a dipole.

"Hydrogen bonding between Na+ ions and a hexane molecule " does not exist since the hydrogen in the hydrogen bond must be bonded directly to an electronegative atom, which hexane does not have since it is a hydrocarbon.

"London dispersion force between two hexane molecules" exist since hexane is a molecular compound.

5 0

2 years ago

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