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Blababa [14]
3 years ago
15

A ____________ alkene is more stable than a ____________ alkene because they have fewer steric interactions. In an elimination r

eaction, a geometry where the β hydrogen and the leaving group are on opposite sides of the molecule is called ____________ periplanar. In an ____________ mechanism, a nucleophile attacks the carbocation, forming a substitution product, while in an ____________ mechanism, a base removes a β hydrogen from the carbocation, forming a new π-bond. CH3CH2Br and NaOH react by an ____________ mechanism. Stronger bases, like hydroxide, favor ____________ reactions, whereas weaker bases, like water favor, ____________ reactions. Disubstituted alkenes always have the possibility to exist as two different ____________ . ____________ reactions are regioselective, favoring formation of the more substituted and more stable alkene
Chemistry
1 answer:
Vesna [10]3 years ago
6 0

Answer:

See explanation

Explanation:

A <u>trans</u> alkene is more stable than a <u>cis alkene</u> because they have fewer steric interactions.

<em>⇒ In a cis alkene there is steric hindrance, because the methyl groups are on the same side of the double bond. </em>

<em>Because of this steric crowding, there are van der Waals repulsive forces between the electron clouds of the groups. </em>

<em> </em>

<em>This decreases the stability of the cis alkene.</em>

<em />

In an elimination reaction, a geometry where the β hydrogen and the leaving group are on opposite sides of the molecule is called <u>anti</u> periplanar.

<em> ⇒ 'Anti’ refers to the two functional groups lying on opposite sides of the plane of the bond</em>

In an <u>SN1 </u>mechanism, a nucleophile attacks the carbocation, forming a substitution product,

<em> ⇒ The SN1 reaction is a substitution reaction, and means "nucleophilic substitution".The "1" says that the rate-determining step is unimolecular. Thus, the rate equation is often shown as having first-order dependence on electrophile and zero-order dependence on nucleophile.</em>

while in an <u>E1</u><u> </u>mechanism, a base removes a β hydrogen from the carbocation, forming a new π-bond.

<em> ⇒ E1 indicates a elimination, unimolecular reaction</em>

<em>This implies that the rate determining step of the mechanism depends on the decomposition of a single molecular species.</em>

<em>.This is a classic elimination reaction – forming a new C–C(π) bond, and breaking a C–H and C–leaving group bond.</em>

CH3CH2Br and NaOH react by an <u>SN2</u><u> </u>mechanism.

<em> ⇒  It's a type of reaction mechanism that is common in organic chemistry, where one bond is broken and one bond is formed, synchronously, (in one step.) </em>

Stronger bases, like hydroxide, favor<u> E2</u> reactions, whereas weaker bases, like water favor, <u>E1</u> reactions

Disubstituted alkenes always have the possibility to exist as two different <u>Diastereomer.</u>

<em>Diastereomer are stereoisomers that are not mirror images of one another and are non-superimposable on one another. They exist (always) in 2 forms.</em>

<u>Elimination reactions</u> are regioselective, favoring formation of the more substituted and more stable alkene.

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450g of chromium(iii) sulfate reacts with excess potassium phosphate. How many grams of potassium sulfate will be produced? (ANS
ExtremeBDS [4]

Answer:

1597.959 g  

Explanation:

Given Data:

Amount of Cr₂(SO₄)₃ = 450 g

Amount of potassium phosphate K₃PO₄ = in Excess

grams of potassium sulfate K₂SO₄= ?

Solution

The Reaction will be

                 Cr₂(SO₄)₃ + 2K₃PO₄  ----------> 3K₂SO₄ + 2CrPO₄

Information that we have from reaction

                Cr₂(SO₄)₃ + 2K₃PO₄  ----------> 3K₂SO₄ + 2CrPO₄

                    1 mol          2 mol                   3 mol

we come to know from the above reaction that

1 mole of chromium(iii) sulfate (Cr₂(SO₄)₃) react with 2 mole of potassium phosphate (K₃PO₄) to produce 3 mole of K₂SO₄

We also know that

molar mass of Cr₂(SO₄)₃ = 147 g/mol

molar mass of K₃PO₄ = 212 g/mol

molar mass of K₂SO₄ = 174 g/mol

if we represent mole in grams then

      Cr₂(SO₄)₃             +       2K₃PO₄          ----------> 3K₂SO₄ + 2CrPO₄

       1 mol (147 g/mol)         2 mol  (212 g/mol)      3 mol  (174g/mol)

So, Now we have the following details

          Cr₂(SO₄)₃  +  2K₃PO₄          ----------> 3K₂SO₄ + 2CrPO₄

              147 g         424 g                           522 g

So,

we come to know that 147 g of Cr₂(SO₄)₃ combine with 424 g of 2K₃PO₄ produce  522 g of K₂SO₄

So now we calculate that how many grams of potassium sulfate will be produced

Apply unity formula

              147 g of  Cr₂(SO₄)₃  ≅ 522 g of K₂SO₄

              450 g of  Cr₂(SO₄)₃  ≅ ? g of K₂SO₄

by doing cross multiplication

g of K₂SO₄ =522 g x 450 g / 147 g

g of K₂SO₄ =  1597.959 g

So the write answer is  1597.959 g  

***Note: By calculation it is obvious that the correct answer is  1597.959 g  

8 0
3 years ago
PLEASE HELPPPP what characteristics of the bond you choose are persent in H2O.​
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6 0
2 years ago
+ H₂O
trapecia [35]

Answer:

None of these are correct, because there is no way to balance this equation, but I hope these steps help you figure out your answer.

Explanation:

Count out the single amounts of elements you have on both sides of the equation. To be balanced, you need to have the exact same for each element.

Before balanced Left side.

Cl-2

O-8

H-2

Before balanced right side.

H-1

Cl-1

O-3

That means we need to increase Hydrogen, Chlorine and Oxygen on the right for sure and see how that affects the equation. You can keep adding the Coefficients until the # of elements begin to match on each side.  

(I tried to balance this equation, it doesn't work, there is too much on the reactants side for what the product is.)

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