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3 years ago

The gravity on Earth is 9.8m/s2, the mass of a bowling ball is about 5kg. What is the weight of the bowling ball on the Earth?

Physics

1 answer:

cupoosta [38]3 years ago

3 0

Answer:

yo can someone answer i need this

Explanation:

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Assuming that voltage remains constant, what happens to the current in a filament if it is replaced by a longer wire?

Elena L [17]

Answer:

Choice B: The current decreases.

Explanation:

The resistance of a conductor is proportional to its length when radius and resistivity stays the same. The resistance of the longer filament will be greater than the resistance of the initial one.

For Ohmic conductors,

$\displaystyle I = \frac{V}{R}$ ,

where

$I$ is the current through the conductor,
$V$ is the voltage across the conductor, and
$R$ is the resistance of the conductor.

Voltage here stays the same. Increasing the resistance $R$ of the conductor will reduce the current.

The filament might heat up over time. The filament might not be an ohmic conductor. Still, a similar trend shall exist. Resistance will be greater in the longer filament, and current will decrease.

4 0

4 years ago

Read 2 more answers

The energy equivalent of the rest mass of an electron is

DerKrebs [107]

Answer:energy times mass

Explanation: yeh

3 0

3 years ago

Relative to the ground, what is the gravitational potential energy of 68 kg

Kisachek [45]

Answer:

Explanation:

p.E=mgh

P.E=68*10*443

p.E=301240j

8 0

2 years ago

mote1985 [20]

Answer:

OC, OD, OA, OB

Explanation:

7 0

3 years ago

A physics professor claims in court that the reason he went through the red light (λ = 660 nm) was that, due to his motion, the

OlgaM077 [116]

Answer:

the speed is 0.53 10⁸ m / s

Explanation:

As say in the exercise, the Doppler effect must be applied, in this case because it is an electromagnetic radiation with speed 3 10⁸ m/s and nothing can go faster we must use the relativistic Doppler effect

fo = fe √[(c-v) /(c + v)]

Where fo is the observed frequency, fe the emitted frequency, c the speed of light and v the relative speed of the observer and emit, it is positive move away

The light fulfills the relationship

c = λ f

f = c / λ

In this case v is negative since the source and the observer approach

Substituting in the equation

c /λo = c /λe √[ (c + v) / (c-v)]

λo = 510 10⁻⁹ m

λe = 610 10⁻⁹ m

We calculate the speed

(λe/λo)² = (c + v) / (c-v)

(λe /λo)² (c-v) = c + v

v +(λe /λo)² v = (λe /λo)² c -c

v [1 +(λe /λo)²] = c [(λe /λo)²-1]

v = c [(λe /λo)² -1] / [1 +(λe /λo)²]

v = 3 10⁸ [(610/510)² -1] / [1+ (610/510)²]

v = 3 10⁸ [1.43-1] / [1 + 1.43]

v = 0.53 10⁸ m / s

A little more about the speed of light

8 0

3 years ago