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PSYCHO15rus [73]
3 years ago
5

A heat engine is a device that converts heat into work. OA. True OB. False

Physics
2 answers:
Rom4ik [11]3 years ago
5 0

Answer:

TRUE APE X VERIFIED  

Explanation:

anygoal [31]3 years ago
4 0

Answer:

A, True.

Explanation:

A heat engine converts heat into mechanical energy.  

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a weightlifter lifts a 1000 newton barbell above his head from the floor to a height of 2.5 meters. he holds the barbell there f
solniwko [45]
Work done = Potential Energy  = (mg)h

               mg   =  weight of the ball
 
               = 1000 N * 2.5 m  = 2500 Joules.

The work done during the 5 second is 2500 Joules.       
7 0
3 years ago
An electric field of 6.1x 10^5 N/C is directed along a charge 2.9 x 10^-19 C. What
Aloiza [94]

Answer:

Electric field is a function 1/r^2

Explanation:

4 0
3 years ago
A 8.0\,\text {kg}8.0kg8, point, 0, start text, k, g, end text box is released from rest at a height y_0 =0.25\,\text my 0 ​ =0.2
Ratling [72]

Answer:

μ = 0.125

Explanation:

To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.

Let's start working on the ramp

starting point. Highest point of the ramp

         Em₀ = U = m h y

final point. Lower part of the ramp, before entering the rough surface

        Em_{f} = K = ½ m v²

as they indicate that there is no friction on the ramp

          Em₀ = Em_{f}

          m g y = ½ m v²

          v = \sqrt{2gy}

we calculate

          v = √(2 9.8 0.25)

           v = 2.21 m / s

in the rough part we use the relationship between work and kinetic energy

          W = ΔK = K_{f} -K₀

as it stops the final kinetic energy is zero

          W = -K₀

The work is done by the friction force, which opposes the movement

          W = - fr x

friction force has the expression

          fr = μ N

let's write Newton's second law for the vertical axis

         N-W = 0

         N = W = m g

we substitute

            -μ m g x = - ½ m v²

           μ = \frac{v^{2} }{2 g x}

Let's calculate

           μ = \frac{2.21^{2}}{2\  9.8\  2.0}

           μ = 0.125

4 0
3 years ago
During 57 seconds of use, 330 C of charge flow through a microwave oven. Compute the size of the electric current.
swat32

Answer:

5.78amps

Explanation:

Given data

Time t= 57 seconds

Charge Q= 330C

Current I= ??

The expression for the electric current is given as

Q= It

Substituting we have

330= I*57

I= 330/57

I=5.78 amps

Hence the current is 5.78amps

3 0
3 years ago
Three science questions help please!
Nimfa-mama [501]
6. D
7. D
8. B
let me know if you need clarification
4 0
4 years ago
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