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Goshia [24]
2 years ago
10

Determine the mass of ammonium chloride, NH4CI, required to prepare 0.250 L of a 0.35 M solution of ammonium chloride.

Chemistry
1 answer:
kkurt [141]2 years ago
7 0
A 0.250 L solution of NH4Cl contains (0.250 L)(0.35 mol/L) = 0.0875 moles of dissolved NH4Cl. Converting this quantity to mass, we get (0.0875 mol NH4Cl)(53.491 g/mol) = 4.7 g NH4Cl (two significant figures).

So, approximately 4.7 g of NH4Cl dissolved in a 0.250 L solution will have a concentration of 0.35 L.
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Answer:

W = -120 KJ

Explanation:

Since the piston–cylinder assembly undergoes an isothermal process, then the temperature is constant.

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Formula for change in entropy is written as;

ΔS = Q/T

Where Q is amount of heat transferred.

Thus;

Q = ΔS × T

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From the first law of thermodynamics, we can find the workdone from;

Q = ΔU + W

Where;

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W = Work done

Now, since it's an ideal gas model, the change in internal energy is expressed as;

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