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Furkat [3]
3 years ago
10

Carbon dioxide at a temperature of 0oC and a pressure of 600 kPa (abs) flows through a horizontal 40-mm- diameter pipe with an a

verage velocity of 2 m/s. Determine the friction factor if the pressure drop is 235 N/m2 per 10-m length of pipe.
Engineering
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

f = 0.04042

Explanation:

temperature = 0°C = 273k

p = 600 Kpa

d = 40 millemeter

e = 10 m

change in  P = 235 N/m²

μ = 2m/s

R = 188.9 Nm/kgk

we solve this using this formula;

P = ρcos*R*T

we put in the values into this equation

600x10³ = ρcos * 188.9 * 273

600000 = ρcos51569.7

ρcos = 600000/51569.7

=11.63

from here we find the head loss due to friction

Δp/pg = feμ²/2D

235/11.63 = f*10*4/2*40x10⁻³

20.21 = 40f/0.08

20.21*0.08 = 40f

1.6168 = 40f

divide through by 40

f = 0.04042

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Answer:

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And replacing in the Carnot efficiency we got:

e= 1- \frac{300.15}{750.15}= 0.59988 = 59.98 \%

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Explanation:

For this case we can use the fact that the maximum thermal efficiency for a heat engine between two temperatures are given by the Carnot efficiency:

e = 1 -frac{T_C}{T_H}

We have on this case after convert the temperatures in kelvin this:

T_C = 27+273.15 = 300.15 K

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And replacing in the Carnot efficiency we got:

e= 1- \frac{300.15}{750.15}= 0.59988 = 59.98 \%

And the maximum power output on this case would be defined as:

W_{max}= e* Q_H = 0.59988 * 65000 \frac{KJ}{min}= 38992.2 \frac{KJ}{min}

Where Q_H represent the heat associated to the deposit with higher temperature.

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