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kiruha [24]
3 years ago
14

Does anyone know the answer to this​

Chemistry
1 answer:
Damm [24]3 years ago
6 0
It’s Tetracarbon dioxide :)
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True or false: Fungi are able to carry out photosynthesis, similar to plants
QveST [7]

Answer:

false

Explanation:

7 0
3 years ago
Read 2 more answers
How many grams of Br are in 335g of CaBr2
ASHA 777 [7]
The answer is 267.93 g

Molar mass of CaBr2 is the sum of atomic masses of Ca and Br:
Mr(CaBr2) = Ar(Ca) + 2Ar(Br)
Ar(Ca) = 40 g/mol
Ar(Br) = 79.9 g/mol
Mr(CaBr2) = 40 + 2 * 79.9 = 199.8 g/mol

The percentage of Br in CaBr2 is:
2Ar(Br) / Mr(CaBr2) * 100 = 2 * 79.9 / 199.8 * 100 = 79.98%

Now make a proportion:
x g in 79.98%
335 g in 100%
x : 79.98% = 335 g : 100%
x = 79.98% * 335 g : 100%
x = 267.93 g
7 0
3 years ago
Anyone know! Please help asap ty
DiKsa [7]

Answer:

An earthquake happens by the child being born from fat mama

Explanation:

6 0
3 years ago
Suppose you are a food chemist working for a company that makes and manufactures soda. Your job is to create a new soft drink wi
Mekhanik [1.2K]

Answer:

The answer to your question is given after the questions so I just explain how to get it.

Explanation:

a)

Get the molecular weight of Phosphoric acid

        H₃PO₄ =  (3 x 1) + (31 x 1) + (16 x 4)

                    = 3 + 31 + 64

                    = 98 g

         98 g -----------------  1 mol

      0.045 g ---------------   x

          x = (0.045 x 1) / 98

          x = 0.045 / 98

          x = 0.00046 moles or 4.6 x 10 ⁻⁴

b)

Molarity = \frac{moles}{volume}

Molarity = \frac{0.00046}{0.35}

Molarity = 0.0013 or 1.31 x 10⁻³

c)

Formula            C₁V₁ = C₂V₂

                              V₁ = C₂V₂ / C₁

Substitution

                              V₁ = (0.0013)(1) / 0.01

Simplification and result

                              V₁ = 0.0013 / 0.1

                              V₁ = 0.13 l = 130 ml            

7 0
3 years ago
Determine how many grams of N2 are produced from the reaction of 8.37 g of H2O2 and 5.29 g of N2H4.
Dmitriy789 [7]
N₂H₄  +  2H₂O₂    →   N₂  +  4H₂O

mol = mass ÷ molar mass

If mass of hydrazine (N₂H₄)  = 5.29 g 
then mol of hydrazine           = 5.29 g ÷ ((14 ×2) + (1 × 4))
                                              = 0.165 mol

mole ratio of hydrazine to Nitogen is     1   :  1
  ∴ if moles of hydrazine = 0.165 mol
     then moles of nitrogen = 0.165 mol

Mass = mol × molar mass

Since mol of nitrogen (N₂)  = 0.165
then mass of hydrazine      = 0.165 × (14 × 2)
                                           = 4.62 g
5 0
3 years ago
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