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Diano4ka-milaya [45]
3 years ago
10

Please help me out i'm so depressed and such a failure

Physics
1 answer:
OverLord2011 [107]3 years ago
3 0

Answer:

b mate im pretty sure ig :)

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A parachutist with a camera, both descending at a speed of 10.8 m/s, releases that camera at an altitude of 50 m. In this proble
Vadim26 [7]

Answer:

The velocity of the camera is 33.11 m/s.

Explanation:

Given that,

Speed = 10.8 m/s

Altitude = 50 m

Suppose determine the velocity of the camera just before it hits the ground?

We need to calculate the velocity of the camera

Using equation of motion

v^2=u^2+2gs

Where, v = final velocity of camera

u = initial speed of camera

s = distance

Put the value into the formula

v^2=(-10.8)^2+2\times(-9.8)\times(-50)

v=\sqrt{1096.64}

v=33.11\ m/s

The direction will be downward so it is the negative velocity.

Hence, The velocity of the camera is 33.11 m/s.

8 0
3 years ago
On the average, about what percentage of the solar energy that strikes the outer atmosphere eventually reaches the earth's surfa
almond37 [142]
I think the answer to your question is twenty-four percent.
5 0
3 years ago
1. Describe the vibration caused by primary waves.
mrs_skeptik [129]
Energy released during an earthquake travels in the form of waves<span> around the Earth. Two types of seismic </span>wave<span> exist, </span>P<span>- and </span>S-waves<span>. They are different in the way that they travel through the Earth. ... They are transverse </span>waves<span> which mean the </span>vibrations<span> are at right angles to the direction of travel.</span>
5 0
4 years ago
Which of the following is not part of a circuit? <br>film <br>Load<br> Key <br>Cell
qaws [65]

Explanation:

I believe <u>f</u><u>i</u><u>l</u><u>m</u><u> </u><u>i</u><u>s</u><u> </u>not part of a circuit

8 0
3 years ago
A plane cruising at 233 m/s accelerates at 17 m/s 2 for 4.8 s. What is its final velocity? Answer in units of m/s. 013 (part 2 o
Volgvan

Answer:

Final velocity will be 314.6 m/sec

Distance traveled = 1314.24 m

Explanation:

We have given initial velocity u = 233 m/sec

Acceleration a=17m/sec^2

Time t = 4.8 sec

From first equation of motion v=u+at, here v is final velocity, u is initial velocity and t is time

So v=233+17\times 4.8=314.6m/sec

Now we have to find distance traveled

From second equation of motion

S=ut+\frac{1}{2}at^2=233\times 4.8+\frac{1}{2}\times 17\times 4.8^2=1314.24m

So distance traveled in given time will be 1314.24 m

4 0
3 years ago
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