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Diano4ka-milaya [45]
2 years ago
10

Please help me out i'm so depressed and such a failure

Physics
1 answer:
OverLord2011 [107]2 years ago
3 0

Answer:

b mate im pretty sure ig :)

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Truck drivers approaching a steep hill that they must climb often increase their speed. What good does this do, if any?
Inga [223]
Um, this doesn't make any sense. By climbing a hill, you are decreasing your momentum and kinetic energy, so it slows you down. The only positive, is after you have climbed the hill, you have more potential energy, and it will be released once you go down the hill, but you will not be as fast as if you ignored the hill.
6 0
3 years ago
What electrical force dies a Uranium nucleus exert on one of its inner electrons, located at a distance of 175 picometers (= 1.7
AlekseyPX

Answer:

correct option is d) 7.0 x 10^-7 N

Explanation:

given data

distance = 175 picometers = 1.75 × 10^{-10}  m

to find out

electrical force

solution

we know atomic no of uranium is 92

and charge on electron is = 1.6 × 10^{-19} C

and electrical force is express as

electrical force = \frac{1}{4 \pi \epsilon _o} \frac{q1q2}{r^2}    .............1

put here value we get

electrical force = 9*10^9 \frac{92*(1.6*10^{-19})^2}{(1.75*10^{-10})^2}

electrical force =  6.921 × 10^{-7} N

so correct option is d) 7.0 x 10^-7 N

5 0
3 years ago
Read 2 more answers
Two students were climbing stairs at school. Student 1 has a weight of 700 N. Student 2 has a weight of 650 N. How much power wo
KIM [24]

Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.

From the question,

We are to calculate the power each student would have to climb the flight of stairs.

Power can be calculated using the formula

P = \frac{F \times d}{t}

Where

P is Power

F is the force

d is the distance

and t is the time

NOTE: The weight of the students represent the force

  • For student 1

F = 700 N

d = 4 m

t = 6 s

∴ P = \frac{700 \times 4}{6}

P = 467 W

  • For student 2

F = 650 N

d = 4 m

t = 6 s

∴ P = \frac{650 \times 4}{6}

P = 433 W

Hence, Student 1 would have a power 467 W and student 2 would have a power of 433 W. The correct option is the fourth option - Student 1 would have 467 W, and Student 2 would have 433 W of power.

Learn more here: brainly.com/question/18801566

3 0
2 years ago
Make a quantitative graph for the motion of the two cars
Andru [333]
It would be helpful if you gave me a bit more information on what the cars speed is
6 0
3 years ago
A solid Cute hug sides 0.50m
irina [24]

Answer:

gg

Explanation:

hh

3 0
3 years ago
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