Answer: it suggests that the positive charge of the gold atom is concentrate at a very small location called the nucleus. The alpha Particles that passes through the gold atom undisturbed must have passed through the sides that is distant from the nucleus
Explanation:
Answer:
9.62 μm
Explanation:
From the question given above, the following data were obtained:
Frequency (f) = 31.2 THz
Wavelength (λ) =..?
Next, we shall convert 31.2 THz to Hz.
This can be obtained as follow:
Recall:
1 THz = 1×10¹² Hz
Therefore,
31.2 THz = 31.2 THz × 1×10¹² Hz / 1 THz
31.2 THz = 3.12×10¹³ Hz
Therefore, 31.2 THz is equivalent to 3.12×10¹³ Hz.
Finally, we shall determine the wavelength (λ) infrared radiation as follow:
Frequency (f) = 3.12×10¹³ Hz.
Velocity (v) = 3×10⁸ m/s
Wavelength (λ) =..?
V = λf
3×10⁸ = λ × 3.12×10¹³
Divide both side by 3.12×10¹³
λ = 3×10⁸ / 3.12×10¹³
λ = 9.62×10¯⁶ m
Converting 9.62×10¯⁶ m to micro metre (μm) we have:
1 m = 1×10⁶ μm
Therefore,
9.62×10¯⁶ m = 9.62×10¯⁶ m × 1×10⁶ μm / 1 m
9.62×10¯⁶ m = 9.62 μm
Therefore, the wavelength of the infrared radiation is 9.62 μm
Answer:
correct answer is d)
Explanation:
This answer demonstrates law of conservation of mass because the mass of the products is equal to the mass of reactants with the help of the coefficients which is the process known as balancing. This answer also includes the correct formulas, as Br is a gas so it MUST be written as Br2. hope this helps:)
The answer is number two here is an explanation of why I said number two ....
In chemistry, orbital hybridisation is the concept of mixing atomic orbitals into new hybrid orbitals suitable for the pairing of electrons to form chemical bonds in valence bond theory.
