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2 years ago

Resolver em c as equações: Z elevado à 2 igual a 3+4i

Engineering

1 answer:

Marrrta [24]2 years ago

3 0

Answer:

Quando um (ou todos) os outros coeficientes de uma equação do segundo grau são iguais a zero, essa equação é chamada incompleta. Neste artigo, analisaremos os métodos que podem ser usados para resolver equações incompletas, no caso em que o coeficiente C = 0, ou seja, o coeficiente é nulo.

Explanation:

Um lado da equação será a potência e outro, o número inteiro. De outro modo, transforme a equação deixando-a isolada em um dos lados. Reescreva a equação. Prepare-a a fim de extrair o logaritmo de ambos os lados, que é o inverso da potência. Você pode calcular o logaritmo de base.

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Meaning of <br> Evaporation

Sedaia [141]

Answer:

The process from a liquid to a vapor.

Explanation:

Water is evaporated by heating up and turning into a vapor.

8 0

3 years ago

Read 2 more answers

The function below takes a two parameters: a list called a_list and a value called a_value. Complete the function to first check

Alik [6]

Explanation:

def checklist(a_list, a_value):// def //used to name a function, the //arguments being passed into the //functions are a_list and a_value

if a_value in list://if statement to

//check if it's in the list or not

print("")//print statement to do

//nothing

else://else statement for if the

//a_value is in a_list

a_list.append(a_value)//this adds

//the value to the list

5 0

3 years ago

Kerosene flows through 3/4 standard type K drawn copper tube. The pressure drop measured at two points 50 m apart is 130 kPa. De

Anettt [7]

Answer:

$Q=4.98\times 10^{-3}\ m^3/s$

Explanation:

Given that

L= 50 m

Pressure drop = 130 KPa

For Copper tube is 3/4 standard type K drawn tube

Outside diameter=22.22 mm

Inside diameter=18.92 mm

Dynamic viscosity for kerosene

$\mu =0.00164\ Pa.s$

Pressure difference given as

$\Delta P=\dfrac{128\mu QL}{\pi d_i^4}$

Where

L is length of tube

μ is dynamic viscosity

Q is volume flow rate

d is inner diameter of tube

ΔP is pressure drop

Now by putting the values

$\Delta P=\dfrac{128\mu QL}{\pi d_i^4}$

$130\times 1000=\dfrac{128\times 0.00164\times 50\times Q}{\pi\times 0.0189^4}$

$Q=4.98\times 10^{-3}\ m^3/s$

So flow rate is $Q=4.98\times 10^{-3}\ m^3/s$

7 0

3 years ago

Wheel diameter 150 mm, and infeed 0.06 mm in a surface grinding operation. Wheel speed 1600 m/min, work speed 0.30 m/s, and cros

gogolik [260]

Answer:

a) the average length per chip is 3 mm

b) the metal removal rate MR is 90 mm³/sec

c) number of chips formed per unit time for the portion of the operation when the wheel is engaged in the work is 4,000,000 chips/min

Explanation:

Given that;

wheel diameter = 150 mm

infeed = 0.06 mm

wheel speed = 1600 m/min = 16000000 mm/s

work speed = 0.30 m/s = 300 mm/s

cross feed = 5 mm

active grits per area = 50 grits/cm²

Average length per chip

Average chip length is given by

Lc = √fd

f is infeed and d is diameter of the wheel

so we substitute

Lc = √( 0.06 × 150

Lc = √ 9

Lc = 3 mm

Therefore the average length per chip is 3 mm

metal removal rate MR is expressed as;

MR = fvc

v is work speed, c is cross feed and f is infeed

so we substitute

MR = 0.06 × 300 × 5

MR = 90 mm³/sec

Therefore the metal removal rate MR is 90 mm³/sec

number of chips formed per unit time is expressed as

No = Vw × c × G

Vw is wheel speed and G is active grits per area

so we substitute

No = 1600000 × 5 × 50/10²

= 4,000,000 chips/min

Therefore number of chips formed per unit time for the portion of the operation when the wheel is engaged in the work is 4,000,000 chips/min

4 0

2 years ago

Calculate the change of entropy of 2 kg of air when its temperature increases from 400 K to 500 K at constant pressure equal to

harkovskaia [24]

Answer:

0.45516

Explanation:

ENTROPY : Entropy is a measure of molecular disorder it is denoted by S. Entropy is also measured in terms of thermal energy and temperature it is equal to thermal energy per unit temperature.

from the table S₁=1.99194 KJ/kg.k (at 400k)

from the table S₂=2.21952 KJ/kg.k (at 500k)

so total entropy change is given by =m (S₂-S₁)

=2(2.21952-1.99194)

=0.45516

4 0

3 years ago