Answer:
q = 38,5 kJ
Explanation:
In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:
q = C×m×ΔT
Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)
Replacing:
q = 4,184J/g°C×92,0g×100°C
q = 38493 J, in kilojoules:
<em>q = 38,5 kJ</em>
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I hope it helps!
Amount of NH3 = 6.39 mol
Ratio of NH3 : Ratio of product
4 : 10
Hence, amount of product formed = 6.39/4 * 10 = 15.975mol = 16.0mol (3sf)
Answer:
1 electron
Explanation:
Look at the periodic table
Li is the 3rd element
now write the electron configuration -> 1s^2 2s^1
the 2nd electron shell has 1 electron as shown above so its 1 electron
