All categories

3 years ago

2. The explosion of nitroglycerin, CHS (NO3)3 , is chemically speaking an instantaneous

Chemistry

1 answer:

frosja888 [35]3 years ago

4 0

Answer: In equation of reaction nitrogen N2 is formed instead of O2

Formula of nitroglycerin is C3H5(NO3)3

Number for N2 is 12. Thus one mole nitroglycerin produces 3 moles N2

Explanation:

You might be interested in

How many moles of oxygen gas are required to form 55g of carbon monoxide gas

marta [7]

Answer:

8.33 moles CO2 X. 25mol O2. 16mol CO2. = 13.0 moles

6 0

3 years ago

40.3 degrees Fahrenheit. Each hour the temperature decreases by 2.09 What is the

Murrr4er [49]

ANSWER

36.12 degrees fahrenheit

6 0

4 years ago

You’ve just started a new job in the laboratory of the Food and Drug Administration. Your supervisor asks you to prepare a 1.50-

anastassius [24]

Answer: 118.5 grams

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in ml = 500 ml

$1.50=\frac{moles\times 1000}{500ml}$

moles = 0.75

moles of solute = $\frac{\text {given mass}}{\text {molar mass}}$

0.75 = $\frac{\text {given mass}}{158g/mol}$

mass of $KMnO_4$ = 118.5 grams

Thus mass of $KMnO_4$ needed to prepare 500 mL of this solution iis 118.5 grams

6 0

3 years ago

Do PV cells last for a long time and are efficient

yulyashka [42]

They do not last forever. And they’re not sufficient

4 0

3 years ago

Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction

AVprozaik [17]

Answer:

The volume of the flask is<u> 20.245 litres .</u>

Explanation:

We are given with following information-

$PV=nRT$ -------- 1

where R = $0.0821L.atom/mole.K$

Molar mass of $PCl_5=208.22g/mole$

The given chemical equation is -

$2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5 _(_s_)$ --------- 2

Now , calculation -

Mass of $PCl_5$ formed = 118g

Molar mass of $PCl_5$ = $208.22g/mole$

Mole = $\frac{mass (g)}{molar mass}$

Therefore , moles of $PCl_5$ formed = $\frac{118}{208.22}$

From equation 2 , we get to know that ,

2mole $PCl_5$ formed from 5 mole $Cl_2 _(_g_)$

Therefore , $\frac{118}{208.22}$ mole $PCl_5$ formed from $\frac{5}{2} \times\frac{118}{208.22}$ mole $Cl_2 _(_g_)$

Moles of $Cl_2 _(_g_)$ used = $\frac{5\times118}{2\times208.22} mole$

R= $0.0821L.atom/mole.K$

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of $Cl_2 _(_g_)$ (n)= $\frac{5}{2} \times\frac{118}{208.22}$ moles

Applying the formula above in 1 equation , that is

PV = nRT

putting the given values -

$1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322$

V = 20.245 litres.

Hence , the volume of the flask is <u>20.245 litres . </u>

8 0

3 years ago