Kc = [CS2] / [S2][C] but, since C is solid, it doesn't fit here
<span>Kc = [CS2] / [S2] </span>
<span>S2(g) + C(s) ---> CS2(g) </span>
<span>13.8mole S2 / 6.05L = 2.28M </span>
<span>Kc = x / 2.28-x </span>
<span>9.4 x (2.28-x) = x </span>
<span>21.43 - 9.4x = x </span>
<span>21.42 = 10.4x </span>
<span>x = 2.05M = [CS2] </span>
<span>2.05M x 6.05L = 12.46moles </span>
<span>12.46moles x 76gmole = 946.96g CS2</span>
Liquids have fixed volume but not fixed shape, so B.
The mass would still be the same 25.0 g but the volume would be bigger
There are approximately 160 grams in 1 mol of Fe2O3 molecules. Therefore, there would be 79/160= 0.49375 mols of Fe2O3 molecules in 79 grams. There are 5 atoms in total for each molecule of Fe2O3, therefore 79/160 * 5 = 79/32 = 2.46875 mols of atoms.
Answer:
Half-life = 3 minutes
Explanation:
Using the radioactive decay equation we can solve for reaction constant, k. And by using:
K = ln2 / Half-life
We can find half-life of polonium-218
Radioactive decay:
Ln[A] = -kt + ln [A]₀
Where:
[A] could be taken as mass of polonium after t time: 1.0mg
k is Reaction constant, our incognite
t are 12 min
[A]₀ initial amount of polonium-218: 16mg
Ln[A] = -kt + ln [A]₀
Ln[1.0mg] = -k*12min + ln [16mg]
-2.7726 = - k*12min
k = 0.231min⁻¹
Half-life = ln 2 / 0.231min⁻¹
<h3>Half-life = 3 minutes</h3>
