A block moving to the right on a level surface with friction is pulled by an increasing horizontal force also directed to the ri
1 answer:
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Answer:
a = 3 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity = 60 [m/s]
Vo = initial velocity = 20 [m/s]
a = acceleration [m/s²]
t = time = 10 [s]
Now replacing these values we have:
60 = 20 + (a*10)
60 - 20 = 10*a
30 = 10*a
a = 3 [m/s²]
Answer:
(I) The momentum of the system is greatest at the point midway between the points X1 and X2; that is X = 20cm. This is because the velocity is maximum at this point. This point is the equilibrium point of the system.
(II) The Kinetic energy of the system is also great at the point midway between the points X1 and X2; X = 20cm
(III) The total energy is greatest at multiple points.
Explanation:
The velocity is greatest at the equilibrium position of the system because the forces responsible for the to and fro movement of the system cancel out of balance up at this point. At any point where there is no net force acting, the acceleration is zero. So at this point the velocity of the body is not changing and has a maximum value. As a result the momentum and kinetic energy of the system will be maximum here too since moment = mv and kinetic energy = ½MV²
The total energy is always the sum of the kinetic and potential energy and at various points the values of the potential and kinetic energies vary from zero to maximum but the total energy is always constant. A simple diagramatic illustration will help to understand this concept. Check the attachment below.
