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monitta
4 years ago
8

Explain why some of the tree get detached from a tree if we vigorously shake it's Branch.​

Physics
2 answers:
Rasek [7]4 years ago
8 0

Answer:

When a tree is vigorously shaken, the branches of the tree come in motion but the leaves tend to continue in their state of rest due to inertia of rest. As a result of this, leaves get separated from the branches of the tree and hence fall down.

oksano4ka [1.4K]4 years ago
6 0

Answer:

When a tree is vigorously shaken, the branches of the tree come in motion moving left and right and shake the leaves off, that's why some of the tree got detached when we vigorously shake its branch.

Explanation:

Like I did in the answer section.

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You throw a ball with a speed of 25.0 m/s at an angle of 40.0â—¦ above the horizontal directly toward a wall. The wall is 22.0 m
Alina [70]

The ball takes about 1.15 seconds to reach the wall

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem!

This problem is about Projectile Motion

<u>Given:</u>

initial speed = u = 25 m/s

angle of speed = θ = 40.0°

horizontal distance = x = 22.0 m

<u>Unknown:</u>

time taken by the ball = t = ?

<u>Solution:</u>

<em>We will use this following formula to find the time taken by the ball to reach the wall:</em>

x = u_x t

x = u \cos \theta ~t

22 = 25 \cos 40^o ~t

t = 22 \div ( 25 \cos 40^o )

t \approx 1.15 \texttt { seconds}

\texttt{ }

<h2>Conclusion :</h2>

The ball takes about 1.15 seconds to reach the wall

\texttt{ }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall

7 0
3 years ago
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Ivanshal [37]

Is this your own answer after the 2 points because if so i would say that is a good answer exept for keeping mountains from growing but they do cause giant black clouds that can block sunlight from the ground below

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3 years ago
A book weighing 18.0 N is lifted from the floor and placed on a shelf 1.5 m high. What is the minimum amount of work required to
algol13
B 12j is the correct answer
6 0
3 years ago
Jorge rides his bicycle to school every morning. The school is 4 km away from Jorge's house and it takes him 30 minutes to ride
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D. Speed
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3 years ago
. A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is orient
Dmitriy789 [7]

Answer:

The magnetic flux through surface is 2.22 \times 10^{-3} Wb

Explanation:

Given :

Magnitude of magnetic field B = 0.078 T

Radius of circle r = 0.10 m

Angle between field and surface normal \theta = 25°

From the formula of flux,

\phi = B.A

\phi = BA\cos \theta

Where \theta = angle between magnetic field line and surface normal, A = area of circular surface.

A = \pi r^{2}

A = 3.14 \times (0.10) ^{2}

A = 0.0314 m^{2}

Magnetic flux is given by,

\phi = 0.078 \times 0.0314 \times \cos 25

\phi = 2.22 \times 10^{-3} Wb

Therefore, the magnetic flux through surface is 2.22 \times 10^{-3} Wb

6 0
4 years ago
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