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monitta
3 years ago
8

Explain why some of the tree get detached from a tree if we vigorously shake it's Branch.​

Physics
2 answers:
Rasek [7]3 years ago
8 0

Answer:

When a tree is vigorously shaken, the branches of the tree come in motion but the leaves tend to continue in their state of rest due to inertia of rest. As a result of this, leaves get separated from the branches of the tree and hence fall down.

oksano4ka [1.4K]3 years ago
6 0

Answer:

When a tree is vigorously shaken, the branches of the tree come in motion moving left and right and shake the leaves off, that's why some of the tree got detached when we vigorously shake its branch.

Explanation:

Like I did in the answer section.

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What are examples of a solution in solids, liquids, and gases
Nina [5.8K]

Answer:

Solid: metal alloy

Liquid: beer

Gas: Air

Explanation:

A solution is a type of mixture where the solvent and solute are homogeneously mixed. Homogeneous mixture means that the solute shouldn't be able to be seen with the naked eye, filtered and stable enough.  

Metal alloy will be an example of a solution in solid-state. Beer is a solution made of liquid alcohol and liquid water. Air mostly composed of nitrogen, but it has oxygen, carbon dioxide, and many other substances in gaseous form.

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3 years ago
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5 0
2 years ago
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What is night vision pls tell fast
mario62 [17]

Answer:

Night vision is when you can see in the dark or at night like owls

Explanation:

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3 years ago
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Uranium has two naturally occurring isotopes. 238u has a natural abundance of 99.3% and 235u has an abundance of 0.7%. it is the
dmitriy555 [2]

The ration of the rms speed of 235uf6 to that of 238uf6 is 1.004.

The molecular mass of 235uf6 is 349, while that of 238uf6 is 352.

The rms speed is calculated as

v=√(3RT/m)

Thus the ratio rms speed of 235uf6 to 238uf6 is calculated as

r=√(352/349)=1.004

6 0
3 years ago
Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance
NemiM [27]

Answer:

Explanation:

Force between two charges of q₁ and q₂ at distance d is given by the expression

F = k q₁ q₂ / d₂

Here force between charge q₁ = - 15 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C when distance between them d = (1.66 - 1.24 ) = .42 mm

k = 1/ 4π x 8.85 x 10⁻¹²

putting the values in the expression

F = 1/ 4π x 8.85 x 10⁻¹²  x - 15 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²

= 9 x 10⁹ x  - 15 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²

= 35969.4 x 10⁻³ N .

force between charge q₂ =  34.5 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C when distance between them d = ( 1.24 - 0 ) = 1.24 mm .

putting the values in the expression

F = 1/ 4π x 8.85 x 10⁻¹²  x  34.5 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²

= 9 x 10⁹ x  - 34.5 x 10⁻⁹ x 47 x 10⁻⁹ /( .42 x 10⁻³)²

= 82729.6  x 10⁻³ N

Both these forces will act in the same direction towards the left (away from the origin towards - ve x axis)

Total force = 118699 x 10⁻³

= 118.7 N.

5 0
3 years ago
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