Question

Please help it's for a test.

Answer 1

Answer:

Explanation:

$KE=\frac{1}{2}mv^2$ so filling in:

$KE=\frac{1}{2}(1000)(30)^2$ so to 2 sig figs (which is actually not accurate, but oh well...)

KE = 450000 J

If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:

450000 = (1000)(9.8)h so

$h=\frac{450000}{(1000)(9.8)}=45.9m$