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galben [10]
2 years ago
6

Two ways the rate of a reaction be monitored

Chemistry
1 answer:
ExtremeBDS [4]2 years ago
3 0

Answer:  If a reaction produces a gas such as oxygen or carbon dioxide, there are two ways to measure the reaction rate: using a gas syringe to measure the gas produced, or calculating the reduction in the mass of the reaction solution.

Explanation:

https://courses.lumenlearning.com/introchem/chapter/measuring-reaction-rates/#:~:text=If%20a%20reaction%20produces%20a,mass%20of%20the%20reaction%20solution.

This is the site I got it from.  I hope this helps.

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How many moles of CO2 are produced when 3.3 moles of C2H2 react
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<span>To solve this exercise you need to know that to create CO₂ with C₂H₂ is necessary to have oxygen. So, the following balanced equation represents the reaction:
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

Notice that 2 moles of C₂H₂ form 4 moles of </span><span>CO₂, so if </span>3.3 moles of C₂H₂ react, how many moles of CO2 would be produced?
2 moles <span>of C₂H₂ -------</span>4 moles of <span>CO₂
3.3 </span><span>moles <span>of C₂H₂--------x moles of CO₂
x=6.6  </span></span><span>moles of CO₂ produced.</span>
5 0
3 years ago
Is an alpha a product or reactant when released from an isotope
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Answer:

Alpha decay

Explanation:

That's the definition of alpha decay

6 0
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Why neutron doesn't contain any charge?​
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Neutron does not contain any charge because the charge of the quarks that made up the neutron balances each other out.

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7 0
1 year ago
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If an object that enters the Earth’s atmosphere does not completely disintegrate, its remains can impact the Earth. True or Fals
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4 0
2 years ago
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A gas mixture is made up of kr (21.7 g), o2 (7.18 g), and co2 (14.8 g). the mixture has a volume of 23.1 l at 59 °c. calculate t
Scilla [17]

Answer:- partial pressure of Kr = 0.306 atm, partial pressure of oxygen = 0.264 atm and partial pressure of carbon dioxide = 0.396 atm

Total pressure is 0.966 atm

Solution:- moles of Kr = 21.7 g x (1mol/83.8g) = 0.259 mol

moles of oxygen = 7.18 g x (1mol/32g) = 0.224 mol

moles of carbon dioxide = 14.8 g x (1mol/44g) = 0.336 mol

Volume of container = 23.1 L and the temperature is 59 + 273 = 332 K

From ideal gas law equation, P = nRT/V

partial pressure of Kr = (0.259 x 0.0821 x 332).23.1 = 0.306 atm

partial pressure of oxygen = (0.224 x 0.0821 x 332)/23.1 = 0.264 atm

partial pressure of carbon dioxide = (0.336 x 0.0821 x 332)/23.1 = 0.396 atm

Total pressure of the gas mixture = 0.306 atm + 0.264 atm + 0.396 atm = 0.966 atm

4 0
3 years ago
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