Answer:
348643.34 barrels of oil
Explanation:
Given;
Volume of the granite = 1 km³ = 1000³ m³
Specific heat of granite, C = 790 J/kg.°C
Density of granite = 2700 kg/m³
Energy in 1 barrel of oil = 6.118 × 10⁹ J
For every 1° change in temperature, ΔT = 1°C
Now,
The thermal energy stored is given as;
Thermal energy = mCΔT
where, m is the mass
the mass of 1 km³ of granite = Density × Volume
or
the mass of 1 km³ of granite = 2700 × 1000³ = 27 × 10¹¹ Kg
therefore,
Thermal energy = 27 × 10¹¹ × 790 × 1
or
Thermal energy = 21330 × 10¹¹ J
hence,
the thermal energy in terms of barrels of oil
= Total thermal energy / Energy stored in 1 barrel of oil
= 21330 × 10¹¹ J / ( 6.118 × 10⁹ J per barrel )
= 348643.34 barrels of oil
