Answer:
2.Closed System: A closed system is a thermodynamic system where energy can be exchanged with its surrounding but not matter. Open System: Open systems can exchange matter with the surrounding. Closed System: Closed systems cannot exchange matter with the surrounding. Open System: The mass of the system will vary with time in open systems.
Explanation:
1.The particle model is the name for the diagrams used to draw solids, liquids and gases. In the model, the particles are shown as circles or spheres. However, the particles in ice, liquid water and steam look the same because they are all water, but in different states of matter. Why do we use the particle model in science?
3.An open system can be defined as a system which can exchange both matter and energy with the surrounding. For example, the earth can be recognized as an open system. In this case, the earth is the system, and space is the surrounding. Sunlight can reach the earth surface and we can send rockets to space.
Answer:
9.9 ml of 0.200M NH₄OH(aq)
Explanation:
3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)
?ml of 0.200M NH₄OH(aq) reacts completely with 12ml of 0.550M FeCl₃(aq)
1 x Molarity NH₄OH x Volume Am-OH Solution(L) = 2 x Molarity FeCl₃ x Volume FeCl₃ Solution
1(0.200M)(Vol Am-OH Soln) = 3(0.550M)(0.012L)
=> Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liter = 9.9 milliliters
Answer:
9
Explanation:
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13 - Periodic table
14 - Dimitri mandeleev
15 - groups
Mark me brainiest pls it right answer
Answer:
Explanation:
AgNO3 + NaCl --> AgCl + NaNO3
Number of moles
AgNO3
= molar concentration * volume
= 1 * 0.01
= 0.01 mol
NaCl
= 0.01 * 1
= 0.01 mol.
By stoichiometry, 1 mole of silver nitrate reacted with 1 mole of NaCl. Therefore,
Number of moles of AgCl formed = 0.01 × 1
= 0.01 mol AgCl formed.
Heat absorbed by solution during precipitation:
Mass of solution = density × total volume
= 1 × 20
= 20 g.
q = m * Cp * (T2 - T1)
= 20 * 4.18 * (32.6 - 25.0)
= 635 J
Since 635 J was absorbed by the solution, the reaction released -635 J
So, Delta H = -635 J/0.01 mol
= -63500 J/mol
= -63.5 kJ/mol.