Wile E. Coyote is chasing the roadrunner and falls off a cliff. It takes Wile E Coyote 7 long seconds to hit the ground. How hig
1 answer:
Answer:
240.1m
Explanation:
Given parameters:
Time taken to hit the ground = 7s
Unknown:
Height of the cliff = ?
Solution:
To solve this problem, we use the right motion equation expressed below:
S = ut + gt²
S is the height of the cliff
u is the initial velocity = 0m/s
g is the acceleration due to gravity = 9.8m/s²
t is the time taken
Now, insert the parameters and solve the problem;
S = (0 x 7) + ( x 9.8 x 7²)
S = 240.1m
You might be interested in
According to Ohm's Law:
Where: V = Voltage
I = Current
R = Resistance
As you can see here, you can say that Current is directly proportional to Voltage and indirectly proportional to Resistance. This means that as the voltage increases, current increases and as the resistance increases, current decreases.
So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved. So the answer to your question is 2. the current will drop to half of its original value.
Where: V = Voltage
I = Current
R = Resistance
As you can see here, you can say that Current is directly proportional to Voltage and indirectly proportional to Resistance. This means that as the voltage increases, current increases and as the resistance increases, current decreases.
So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved. So the answer to your question is 2. the current will drop to half of its original value.
Answer:
The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Explanation:
Given;
number of turns of the flat circular loop, N = 18 turns
radius of the loop, R = 15.0 cm = 0.15 m
current through the wire, I = 0.51 A
The magnetic field through the center of the loop is given by;
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.