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Olenka [21]
2 years ago
13

Which of the following has potential but not kinetic energy?

Physics
1 answer:
marissa [1.9K]2 years ago
7 0

A ball sitting on a shelf:)

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A dentist’s drill starts from rest. After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min. Find the
mylen [45]

Answer:

Angular acceleration, is 708.07\ rad/s^2

Explanation:

Given that,

Initial speed of the drill, \omega_i=0

After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed, \omega_f=28940\ rev/min=3030.58\ rad/s

We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.

\alpha =\dfrac{\omega_f}{t}\\\\\alpha =\dfrac{3030.58\ rad/s}{4.28\ s}\\\\\alpha =708.07\ rad/s^2

So, the drill's angular acceleration is 708.07\ rad/s^2.

4 0
2 years ago
Which is the pathway for information through a neuron?
Mariulka [41]
Information travels along the axon once an impulse is received. The axon then takes it to the place where it can be sent off to another neuron

<span>dendrite → cell body → axon → axon terminals is the correct answer</span>

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6 0
3 years ago
Read 2 more answers
Henry mixed salt and water together in a cup until he observed a clear solution. He measured the mass of the solution. Then he p
lapo4ka [179]

Answer:

He is incorrect. Dissolving salt in water and evaporation of the water are both physical changes. The reappearance of salt is evidence that the change was reversible by a physical change, so it could not be a chemical change.

6 0
2 years ago
Why would a atomic nucleus give off a particle
pickupchik [31]
<span>A atomic nucleus would give off a particle to become stable. 

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4 0
2 years ago
A positive charge (q = +6.0 µC) starts from point A in a constant electric field and accelerates to point B. The work done by th
riadik2000 [5.3K]

Vb - Va = -366.7 V.

Vab = Va - Vb, the potential of a with respect to b, is equal to the work done by the electric force when a unit of charge moves from a to b, it is given by:

Vab = Va - Vb = Wab/q,

So, in order to determinate the potential difference Vb - Va we have to multiply by -1 both side of the equation above:

- (Va - Vb) = - (Wab/q)

Resulting

Vb - Va = -(Wab/q)

Given a positive charge q = 6.0μC = 6.0x10⁻⁶C, Wab = 2.2x10⁻³J. Determine Vb - Va.

Vb - Va = - (2.2x10⁻³J/6.0x10⁻⁶C)

Vb - Va = -366.7 J/C = -366.7 V

8 0
2 years ago
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