Answer: µ=0.205
Explanation:
The horizontal forces acting on the ladder are the friction(f) at the floor and the normal force (Fw) at the wall. For horizontal equilibrium,
f=Fw
The sum of the moments about the base of the ladder Is 0
ΣM = 0 = Fw*L*sin74.3º - (25.8kg*(L/2) + 67.08kg*0.82L)*cos74.3º*9.8m/s²
Note that it doesn't matter WHAT the length of the ladder is -- it cancels.
Solve this for Fw.
0= 0.9637FwL - (67.91L)2.652
Fw=180.1/0.9637
Fw=186.87N
f=186.81N
Since Fw=f
We know Fw, so we know f.
But f = µ*Fn
where Fn is the normal force at the floor --
Fn = (25.8 + 67.08)kg * 9.8m/s² =
910.22N
so
µ = f / Fn
186.81/910.22
µ= 0.205
Answer:
Orange , yellow, green and blue
red coat absorbs all colors of visible light except red, so red light
is the only light left to bounce off of the coat toward our eyes.
For n resistors in series, the equivalent resistance is given by the sum of the resistances:

In this problem, we have three resistors, so the equivalent resistance of the load is the sum of the resistances of the three resistors:
Answer:Given mass = 4.1kg
Radius = 0.0117m
Velocity V = 8.4m/s
Coefficient of friction = 0.25
Explanation: Below is an attached solution to the problem stated above.
1. The angular acceleration is equal to 524rad/s^2
2. The linear acceleration is equal to 2.45m/s^2
3.the time it takes the ball to begin rolling = 0.98s
4. The distance the ball slides before it begins to roll = 7.05m