Assume that the concentration of stock is 1.0 M
And initial volume = 16.0 ml
final volume = 0.310 L or 310 ml
therefore
CiVi = CfVf
1.0 *16 ml = Cf * 310 ml
Cf = 1.0*16/310
= 0.052 M
Thus dilute solution is 0.052 M times dilute to concentrate solution
Answer: since water is denser than the ice, the ice, floats to the top
Explanation:
Answer:
D & E
Explanation:
I think this is dealing with latent heat and D & E would be the range where you will find solid and liquid phases in equilibrium, cuz it starts as gas at from A to B, B to C is gas and liquid equilibrium, C to D is liquid, D to E solid and liquid, and then E to F is solid.
Answer:
0.38dm³ or 38mL
Explanation:
Given parameters:
molarity of HCl = 5.5M
volume of Mg(OH)₂ = 85mL
molarity of Mg(OH)₂ = 1.22M
Unknown:
Volume of HCl solution = ?
Solution:
we have to adopt the mole concept to solve this problem.
Complete reaction equation:
2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O
For a standard acid titrated against a standard base,
aA + bB → cC + dD
A is the acid, B is the base
since number of moles = C x V
C is the molarity
V is the volume
CₐVₐ / CₓVₓ = a / x
a = acid
x = base
85mL to dm³ = 0.085dm³
since the unknown is Vₐ,
let us make it the subject of the expression;
Vₐ = (a/x) x ( CₓVₓ/ Cₐ)
Va = = 0.38dm³