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kiruha [24]
4 years ago
13

A multipurpose transformer has a secondary coil with several points at which a voltage can be extracted, giving outputs of 5.60,

12.0, and 480 V. (a) The input voltage is 140 V to a primary coil of 220 turns. What are the numbers of turns in the parts of the secondary used to produce the output voltages
Engineering
1 answer:
Rudik [331]4 years ago
4 0

Answer:

for 5.6V 9 turns, for 12.0V 19 turns, for 480V 755 turns

Explanation:

Vp/Vs= Np/Ns

Vp: Primary voltage

Vs: Secondary Voltage

Np: number of turns on primary side

Ns: number of turns on secondary side

for output 5.6V

140/5.6= 220/Ns

Ns= 8.8 or 9 Turns

for output 12.0V

140/12= 220/Ns

Ns= 18.9 or 19 turns

for output 480V

140/480= 220/Ns

Ns= 754.3 or 755 turns

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primary consumer because YES

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A heat engine that receives heat from a furnace at 1200°C and rejects waste heat to a river at 20°C has a thermal efficiency of
viktelen [127]

Answer:

second-law efficiency  = 62.42 %

Explanation:

given data

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temperature T2 = 20°C  =  293 K

thermal efficiency η = 50 percent

solution

as we know that thermal efficiency of reversible heat engine between same  temp reservoir

so here

efficiency ( reversible ) η1 = 1 - \frac{T2}{T1}      ............1

efficiency ( reversible ) η1  = 1 - \frac{293}{1473}  

so efficiency ( reversible ) η1  = 0.801

so here second-law efficiency of this power plant is

second-law efficiency = \frac{thernal\ efficiency}{0.801}

second-law efficiency = \frac{50}{0.801}  

second-law efficiency  = 62.42 %

3 0
3 years ago
section 10.1 describes a man in the middle attack on the diffie-hellman key exhange protocal in which the adversary generates tw
nika2105 [10]

Answer:

1. James will attack by generating a random private key XD and a corresponding public key YD.

2. Jane transmit YA to another person called Alex.

3. James intercept YA and transmit YD to jane.

4. Jane receive YD and calculate K1

At this point james and jane thinks they share a secret key but instead james has a secret key k1 to Jane and k2 to alex.

5. Alex transmit another key XA to alex for example.

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6 0
3 years ago
The elevation of the end of the steel beam supported by a concrete floor is adjusted by means of the steel wedges E and F. The b
Wewaii [24]

Answer:

a) P ≥ 22.164 Kips

b) Q = 5.4 Kips

Explanation:

GIven

W = 18 Kips

μ₁ = 0.30

μ₂ = 0.60

a) P = ?

We get F₁  and F₂ as follows:

F₁ = μ₁*W = 0.30*18 Kips = 5.4 Kips

F₂ = μ₂*Nef = 0.6*Nef

Then, we apply

∑Fy = 0   (+↑)

Nef*Cos 12º -  F₂*Sin 12º = W

⇒   Nef*Cos 12º -  (0.6*Nef)*Sin 12º = 18

⇒   Nef = 21.09 Kips

Wedge moves if

P ≥ F₁ + F₂*Cos 12º + Nef*Sin 12º

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We can see the pic shown in order to understand the question.

7 0
3 years ago
Read 2 more answers
A tool chest has 950 N weight that acts through the midpoint of the chest. The chest is supported by feet at A and rollers at B.
Mazyrski [523]

Answer:

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the motion sliding

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F = 0.3*475 N

F = 142.5 N (←)

we can apply

P - F  > 0

P  > 142.5 N (→)

the motion sliding

6 0
3 years ago
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