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GenaCL600 [577]
3 years ago
11

Using a flowchart, discuss how a tsunami develops?​

Physics
1 answer:
Ahat [919]3 years ago
4 0

Answer:

A tsunami is a sequence of particularly long water waves that can spread over very great distances and, as such, cause water to move.

When penetrating into areas of shallow water, the sea is compressed and thus piles up on the coasts to form several high tidal waves. These carry the water with great force far over the shoreline and usually cause great damage. During the subsequent retreat, the material carried away on the flooded land, often also people and animals, is mostly washed far out into the ocean.

Tsunamis occur as a result of sudden water displacement, such as when parts of the ocean floor are raised or lowered during an undersea earthquake or when large masses of earth and rock slide into the water as well as due to violent winds.

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"a horn emits a frequency of 1000 HZ. A 14 m/s wind is blowing toward a listener. What is the frequency of the sound heard by th
Semenov [28]

Answer:

 f_L = 1000 Hz

Explanation:

given,

speed of wind, = 14 m/s

frequency of horn,f_s = 1000 Hz

speed of sound,V = 344 m/s

frequency heard by the listener

using Doppler effect

f_L = \dfrac{v+v_L}{v+v_s}f_s

f_L is the frequency of the sound heard by the listener

f_s is the frequency of sound emitted by the listener

V is the speed of sound

v_L is the speed of listener

v_s is the speed of source

now,

considering the frame of reference in which wind is at rest now, both listener and the source will be moving at 14 m/s

 f_L = \dfrac{v+14}{v+14}\times 1000

now on solving we will get

 f_L = 1000 Hz

hence, the frequency heard by the listener is equal to  1000 Hz

 

7 0
3 years ago
As the wavelength of electromagnetic radiation increase
Dominik [7]

Answer:

the frequency and the radiation of radiation decreases.

Explanation:

7 0
2 years ago
A car accelerates from rest at a constant rate of 1.6
SIZIF [17.4K]

Answer:

8m/s

Explanation:

it says that its at a constant rate of 1.6 that means it doesn't change and the car accelerates for 5 seconds so 1.6 X 5 which is 8

7 0
3 years ago
Calculate the first and second velocities of the car with four washers attached to the pulley, using the formulas v1 = 0. 25 m /
castortr0y [4]

The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Given data:

The value of the first distance is, d1 = 0.25 m.

The value of the second distance is, d2 = 0.50 m.

The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

v = d/t

Here,

d is the distance covered.

t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

here, t1 is the average time for first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

v2 = d2/t2

v2 = 0.50 /t2

here, t2 is the average time for the second distance.

Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Learn more about the velocity here:

brainly.com/question/862972

6 0
2 years ago
I need someone to give me 2 answers,
yanalaym [24]
Uh.. what's the question..?
8 0
3 years ago
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