If a wire with current 5.0a has 12 coulombs of charge pass through it how much time has passed
1 answer:
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Answer:
mm
Explanation:
As we know that
where
m represents the order of minimum
y represents the distance on the screen of the minimum from central axis
λ is the wavelength of the light
D is the distance between screen-to-slit
d represents the width of the slit
For first minima
For second minima
Answer:
hello your question is incomplete attached below is the complete question
answer :
20.16 v
Explanation:
The reading of the voltmeter at the instant the switch returns to position a
L = 5H
i ( current through inductor ) = 1/L ∫ V(t) d(t) + Vo
= 1/5 ∫ 3*10^-3 d(t) + 0 = 0.6 * 10^-3 t
iL ( 1.6 s ) = 0.6 * 10^-3 * 1.6 = 0.96 mA
Rm ( resistance ) = 21 * 1000 = 21 kΩ
The reading of the voltmeter ( V )
V = IR
= 0.96 mA * 21 k Ω = 20.16 v
Answer:
Acceleration:
From third equation: