Answer:
6.28 L
Explanation:
Given data:
Volume of NO₂ = ?
Mass of NO₂ = 12.9 g
Temperature and pressure = ?
Solution:
First of all we will calculate the number of moles of gas.
Number of moles = mass/molar mass
Number of moles = 12.9 g/ 46 g/mol
Number of moles = 0.28 mol
At standard temperature and pressure 1 mole of gas occupy 22.4 L volume.
Thus,
0.28 mol × 22.4 L/1 mol
6.27 L ≅ 6.28 L
The answer is: volume of ammonia gas is 7.4 L.
Chemical reaction: 6NO + 4NH₃ → 5N₂ + 6H₂O.
m(NO) = 15 g; mass of nitrogen(II) oxide.
M(NO) = 30 g/mol; molar mass of nitrogen(II) oxide.
V(NH₃) = ?
n(NO) = 15 g ÷ 30 g/mol.
n(NO) = 0.5 mol; amount of nitrogen(II) oxide.
From chemical reaction: n(NO) : n(NH₃) = 6 : 4.
0.5 mol : n(NH₃) = 6 : 4.
n(NH₃) = 0.33 mol; amount of ammonia.
Vm = 22.4 L/mol; molar volume at STP.
V(NH₃) = 0.33 mol · 22.4 L/mol..
V(NH₃) = 7.4 L.
In order to calculate the percentage composition of a certain element, certain steps are followed:
1- You get the the molar mass of the component you wish to find its percentage in units of gm/mole.
2- You then get the molar of the whole given compound
3- You the divide the molar mass of the desired component by the total molar mass of the compound and then multiply the output by 100 to get the percentage.
As you can see, calculating the percentage is dependent on the mass and not the volume
They have increased number of protons which is the atomic number.
Explanation:
20984Po→20582Pb+42α
4520Ca→4521Sc+0-1e+00ν
Explanation:
The alpha decay of polonum-209, which consists of the emission of an alpha particle, will leave behind the atom of a different element.
Notice that the identity of the element changes after the decay. This means that you're dealing with a nuclear transmutation, a process that converts an atom of a given element into an atom of a different element.