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faust18 [17]
2 years ago
9

A cylindrical space capsule lands in the ocean. This capsule is 2.44 m long, 1.10 m in diameter, and weighted at one end so that

it floats with its long central axis vertical and 0.820 m of its length above the water surface. The mass density of sea water is 1025 kg/m3.What is the magnitude of the buoyant force exerted on the capsule?
Engineering
1 answer:
sukhopar [10]2 years ago
7 0

Answer:

The correct answer is "15456.8 N".

Explanation:

According to the question,

The inside volume will be:

= 3.14\times (\frac{1.1}{2} )^2\times (2.44-0.82)

= 3.14\times \frac{1.21}{4}\times 1.62

= 3.14\times 03025\times 1.62

= 1.538757 \ m^3

hence,

The buoyant force will be:

= V\times Pw\times g

= 1.538757\times 1025\times 9.8

= 15456.8 \ N

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Technician A is correct.

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2 years ago
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saul85 [17]

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Thanks for the help!
Dafna11 [192]

Answer:

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Explanation:

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