Question

A cylindrical space capsule lands in the ocean. This capsule is 2.44 m long, 1.10 m in diameter, and weighted at one end so that it floats with its long central axis vertical and 0.820 m of its length above the water surface. The mass density of sea water is 1025 kg/m3.What is the magnitude of the buoyant force exerted on the capsule?

Answer 1

Answer:

The correct answer is "15456.8 N".

Explanation:

According to the question,

The inside volume will be:

= $3.14\times (\frac{1.1}{2} )^2\times (2.44-0.82)$

= $3.14\times \frac{1.21}{4}\times 1.62$

= $3.14\times 03025\times 1.62$

= $1.538757 \ m^3$

hence,

The buoyant force will be:

= $V\times Pw\times g$

= $1.538757\times 1025\times 9.8$

= $15456.8 \ N$