Answer:
205 K (to 3 significant figures)
Explanation:
Assuming that 4 moles of the gas behaves like an ideal gas and obey the kinetic molecular theory.
Let's apply the ideal gas law, pV= nRT.
Here p denotes the pressure of the gas, V is for volume, n is the number of moles of the gas, R is the universal gas constant and T is the temperature.
Substitute the given information into the equation:
5.6 atm ×12 L= 4 mol ×R ×T
Since pressure is in atm and volume is in L, we can use R= 0.08206 L atm K⁻¹ mol⁻¹.
5.6 atm ×12 L= 4 mol ×0.08206 L atm K⁻¹ mol⁻¹ ×T
T= 67.2 ÷0.32824
T= 204.73 (5 s.f.)
T= 205 K (3 s.f.)
Answer:
<h3>The answer is 1.30288 × 10³ g</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume = 95.8mL
density = 13.6g/mL
We have
mass = 13.6 × 95.8 = 1302.88
We have the final answer as
<h3>1.30288 × 10³ g</h3>
Hope this helps you
When you work with molar mass, you solve for the quantity of ''Moles'' within the substance by converting Mass. The way you can tell the equation is balanced would be by knowing whether the moles were equivalent on both sides or not. Therefore, if they are equal, it is balanced considering you have the same amount of moles on each side of the equation.
Answer:a quantum absorption of energy
Explanation:
Bohr’s model explains the spectral lines .While the electron of the atom remains in the ground state, its energy is unchanged. When the atom absorbs one or more quanta of energy, the electron moves from the ground state orbit to an excited state and when the atom relaxes back to a lower energy state, it releases energy that is again equal to the difference in energy of the two orbits.
Explanation:
Reaction equation is as follows.
Here, 1 mole of 
produces 2 moles of cations.
![[Na^{+}] = 2[Na_{2}SO_{3}] = 2 \times 0.58](https://tex.z-dn.net/?f=%5BNa%5E%7B%2B%7D%5D%20%3D%202%5BNa_%7B2%7DSO_%7B3%7D%5D%20%3D%202%20%5Ctimes%200.58)
= 1.16 M
![[SO^{2-}_{3}] = [Na_{2}SO_{3}]](https://tex.z-dn.net/?f=%5BSO%5E%7B2-%7D_%7B3%7D%5D%20%3D%20%5BNa_%7B2%7DSO_%7B3%7D%5D)
= 0.58 M
The sulphite anion will act as a base and react with 
to form 
and 
.
As, 
= 
= 
According to the ICE table for the given reaction,
Initial: 0.58 0 0
Change: -x +x +x
Equilibrium: 0.58 - x x x
So,
![K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}](https://tex.z-dn.net/?f=K_%7Bb%7D%20%3D%20%5Cfrac%7B%5BHSO%5E%7B-%7D_%7B3%7D%5D%5BOH%5E%7B-%7D%5D%7D%7B%5BSO%5E%7B2-%7D_%7B3%7D%5D%7D)
x = 0.0003 M
So, x = ![[HSO^{-}_{3}] = [OH^{-}]](https://tex.z-dn.net/?f=%5BHSO%5E%7B-%7D_%7B3%7D%5D%20%3D%20%5BOH%5E%7B-%7D%5D)
= 0.0003 M
![[SO^{2-}_{3}]](https://tex.z-dn.net/?f=%5BSO%5E%7B2-%7D_%7B3%7D%5D)
= 0.58 - 0.0003
= 0.579 M
Now, we will use ![[HSO^{-}_{3}]](https://tex.z-dn.net/?f=%5BHSO%5E%7B-%7D_%7B3%7D%5D)
= 0.0003 M
The reaction will be as follows.
Initial: 0.0003
Equilibrium: 0.0003 - x x x
= 
= 
Therefore, 
As, x <<<< 0.0003. So, we can neglect x.
Therefore, 
= 
x = 
x = ![[OH^{-}] = [H_{2}SO_{3}]](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%20%5BH_%7B2%7DSO_%7B3%7D%5D)
= 
![[H^{+}] = \frac{10^{-14}}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B10%5E%7B-14%7D%7D%7B%5BOH%5E%7B-%7D%5D%7D)
= 
= 
M
Thus, we can conclude that the concentration of spectator ion is M.
