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Verizon [17]
3 years ago
14

In an experiment conducted between oxygen and chlorine gas it was found that oxygen gas spread much faster than chlorine. What i

s the explanation for this observation?
Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
4 0

Answer:

Because oxygen is lighter

Explanation:

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When you get injured or hurt it affects the nervous system and let’s it react by the severity.
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A reaction that is NOT thermodynamically favored at low temperatures can become thermodynamically favored at high temperatures
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3 years ago
Calculate δs∘rxn for the reaction2no(g) o2(g)→2no2(g)express your answer to one decimal place and include the appropriate units
Anna35 [415]

The δs∘rxn  for the reaction 2NO(g) + O_{2} → 2NO_{2} (g) will be -146 J/K.

Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.

Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit JK^{-1} mol^{-1}.

Entropy of the reaction can be calculated by the reaction.

ΔS^{0} rxn = 2 mol × S^{0} (NO_{2} (g) - 2 mol × S^{0} NO (g) - 1 mol × S^{0} (O_{2} )

ΔS^{0} rxn  = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K

ΔS^{0} rxn  = -146.8 J/K

Therefore, the δs∘rxn  for the reaction 2NO(g) + O_{2} → 2NO_{2} (g) will be -146 J/K.

To know more about reaction

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4 0
1 year ago
A sample of metal has a mass of 5. 2 g and absorbs 20. 0 j of energy as it is heated from 30. 0°c to 40. 0°c. What is the identi
kiruha [24]

The identity of the metal is copper.

<h3>What is specific heat?</h3>

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

Using the formula of specific heat

H = mcdT

Where, H = Heat absorbed

m = mass of the metal

c = specific heat capacity of the metal

dT = temperature change

Putting the values in the equation

20 J = 0.0052 Kg × c × ( 40.0°C - 30.0°C)

c = 20 J/0.0052 Kg × ( 40.0°C - 30.0°C)

c = 385 JKg-1°C-1

Thus, the metal is copper.

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6 0
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