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Harman [31]
3 years ago
10

Explain the process of ionic bond formation between K( potassium a metal) and Br(bromine a nonmetal)

Physics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0
Potassium belongs to group IA of the elements. This means that it will give up one of its electrons to form the cation K+. Opposite to that is bromine in which it accepts one electrons to form the anion Br-. The binding of these elements will form KBr and is formed from transfer of electron from one element to the other. This is the mechanism of ionic bond formation.
Ipatiy [6.2K]3 years ago
7 0
Metals transfers electrons to nonmetals. So K transfers one electron to Br because K is located at 1A in the periodic table. Br has seven electrons, now both K and Br are stable by gaining and losing one electron. <span>The transfer of electrons makes metals</span> <span>to become </span>positive ions <span>and </span>nonmetal <span>to become </span>negative ions. When a<span>n ionic bond is formed, the charges attract each other.</span>
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The temperature of a black body is 500 and its radiation is of wavelength 600 . If the number of oscillators with energy is 100
stiks02 [169]

Answer: An equation is missing in your question below is the missing equation

a) ≈ 8396

b) 150 nm/k

Explanation:

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number of oscillators = 8395

attached below is the detailed solution

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applying Wien's law / formula

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b = 3 * 10^6 nm

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3 years ago
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solmaris [256]

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\frac{4}{\sqrt{45} } i\,+\frac{2}{\sqrt{45} } j-\frac{5}{\sqrt{45} } k

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