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Harman [31]
3 years ago
10

Explain the process of ionic bond formation between K( potassium a metal) and Br(bromine a nonmetal)

Physics
2 answers:
SVETLANKA909090 [29]3 years ago
8 0
Potassium belongs to group IA of the elements. This means that it will give up one of its electrons to form the cation K+. Opposite to that is bromine in which it accepts one electrons to form the anion Br-. The binding of these elements will form KBr and is formed from transfer of electron from one element to the other. This is the mechanism of ionic bond formation.
Ipatiy [6.2K]3 years ago
7 0
Metals transfers electrons to nonmetals. So K transfers one electron to Br because K is located at 1A in the periodic table. Br has seven electrons, now both K and Br are stable by gaining and losing one electron. <span>The transfer of electrons makes metals</span> <span>to become </span>positive ions <span>and </span>nonmetal <span>to become </span>negative ions. When a<span>n ionic bond is formed, the charges attract each other.</span>
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ki77a [65]

Answer:

a. Zin = 41.25 - j 16.35 Ω

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a.

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Zin = 50 * [ 75 + j 50 Tan (54) ] / [ 50 + j 75 Tan (54) ]

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b.

I₁ = Vg / Zg + Zin ⇒ I₁ = 300 / 41.25 - j 16.35 = 3.24 e ¹⁰ ¹⁶

V₁ = I₁ * Zin = 3.24 e ¹⁰ ¹⁶ * ( 41.25 - j 16.35)

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c.

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d.

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PL = 216 w

e.

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