Elements in group 16 want to bond with elements in group ___.

Chemistry

1 answer:

Trava [24]3 years ago

5 0

Answer:

Two

Explanation:

Elements in group 16 wants to bond with elements in group IIA, the group of alkaline earth metals.

The bonding will make it easier for them complete their octet.
Elements in group 16 has 6 valence electrons.
To have a complete octet, they require 2 more electrons.
Group II elements are willing donors as they are metals.
For Group II elements to fill their octets, they must lose two electrons.
So the willingness of group II elements to lose two electrons and the readiness for group 16 elements to gain the electrons makes the desire one another.

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In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to anot

forsale [732]

The given question is incomplete . The complete question is :

In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to another. What are the new relative charges between the two atoms?

a. The giving atom and receiving atom are both negatively charged

b. The giving atom is now positively charged and the receiving atom is now negatively charged.

c. The giving and receiving atom are both positively charged

d. The giving atom is now negatively charged and the receiving atom is now positively charged.

Answer: The giving atom is now positively charged and the receiving atom is now negatively charged.

Explanation:

Ionic compounds are formed by transference of electrons between metals and non metals. The bond formed between a metal and a non-metal is always ionic in nature.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Thus when one electron moves from one atom to another, the metal acquires a positive charge and the non metal acquires negative charge.

For example: $NaCl$ is formed by transfer of one electron from sodium to chlorine , thus forming $Na^+$ and $Cl^-$