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ludmilkaskok [199]
3 years ago
10

Lint boy leaves the secret Fuzz Fortress at 10:30 in the morning. He uses his super static cling action to propel himself 2700 m

iles by 1:30 in the afternoon. How fast was he going?
Physics
1 answer:
Anon25 [30]3 years ago
4 0
I have no clue lol ok
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What is the difference in KE between a 52.5 kg person running 3.50 m/s and a 0.0200 kg bullet flying 450 m/s?
rusak2 [61]

Answer:

Ek = 1705.28 [J]

Explanation:

In order to solve this problem, we must remember that kinetic energy can be calculated by means of the following equation.

E_{k}=\frac{1}{2} *m*v^{2}

where:

m = mass [kg]

v = velocity [m/s]

Ek = kinetic energy [J] (Units of Joules)

<u>For the person running</u>

<u />E_{k} =\frac{1}{2}*52.2*(3.5)^{2} \\ E_{k} =319.72[J]<u />

<u />

<u>For the bullet</u>

<u />E_{k} =\frac{1}{2} *m*v^{2}<u />

<u />E_{k} =\frac{1}{2} *0.02*(450)^{2} \\E_{k}=2025 [J]<u />

<u />

The difference in Kinetic energy is equal to:

Ek = 2025 - 319.72

Ek = 1705.28 [J]

8 0
3 years ago
Calculate the wavelengths of the first five members of the Lyman series of spectral lines, providing the result in units Angstro
Oduvanchick [21]

Answer:

Explanation:

The formula for hydrogen atomic  spectrum is as follows

energy of photon due to transition from higher orbit n₂ to n₁

E=13.6 (\frac{1}{n_1^2 } - \frac{1}{n_2^2})eV

For layman series n₁ = 1 and n₂ = 2 , 3 , 4 ,   ...   etc

energy of first line

E_1=13.6 (\frac{1}{1^2 } - \frac{1}{2 ^2})

10.2 eV

wavelength of photon = 12375 / 10.2 = 1213.2 A

energy of 2 nd line

E_2=13.6 (\frac{1}{1^2 } - \frac{1}{3 ^2})

= 12.08 eV

wavelength of photon = 12375 / 12.08 = 1024.4 A

energy of third line

E_3=13.6 (\frac{1}{1^2 } - \frac{1}{4 ^2})

12.75 e V

wavelength of photon = 12375 / 12.75 = 970.6 A

energy of fourth line

E_4=13.6 (\frac{1}{1^2 } - \frac{1}{5 ^2})

= 13.056 eV

wavelength of photon = 12375 / 13.05 = 948.3 A

energy of fifth line

E_5=13.6 (\frac{1}{1^2 } - \frac{1}{6 ^2})

13.22 eV

wavelength of photon = 12375 / 13.22 = 936.1 A

7 0
3 years ago
Pls help meh Kdjdjeidjndiejdididjdjjdidjdjdiejd
Nadya [2.5K]

Answer:

i think b

Explanation:

i'm not sure

6 0
3 years ago
Read 2 more answers
Air can be humidified by passing through a long tube whose inside diameter is lined with a wick saturated with liquid water. The
Oduvanchick [21]

Answer:

IV because the process of water is equal to 5,8 to 783253.23 to the hendroxagram of 4.

Explanation:

4 0
3 years ago
A rescue plane flying horizontally at 72.6 m / s spots a survivor in the ocean 182 m directly below and releases an emergency ki
Mila [183]

Answer:

547 m

Explanation:

From law of motion

s = ut + ½at²

Where "t" is Time taken to reach Earth

s= distance= 182 m

a= vertical acceleration = 5.82 m / s 2

U= initial velocity in vertical position = 0

182= ½ × 5.82t²

t²=( 2× 182)/ 5.82

= 364/5.82

= 62.54

t= √62.54

t= 7.908s

horizontal distance travelled = speed x time

Horizontal speed= 72.6 m / s

horizontal distance travelled =72.6× 7.908

= 547 m

Hence, the survivor will it hit the waves at 547 m away

3 0
3 years ago
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