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11Alexandr11 [23.1K]
3 years ago
11

A 500kg car is driving through a neighborhood at 20m/s. Then the car hits a speed bump which causes it to slow to 15m/s. What wa

s the impulse delivered by the speed bump to the car?
Physics
1 answer:
lawyer [7]3 years ago
5 0

Based on the formula for calculating impulse, the impulse of the speed bump to the car is 2500 Ns.

<h3>What is the impulse of the speed bump?</h3>

  • Impulse = change in momentum
  • momentum = mass * velocity

Change in momentum = mu - mv

where u is initial velocity

v is final velocity

Impulse = 500 * 20  - 500 * 15

Impulse = 2500 Ns

Therefore, the impulse of the speed bump to the car is 2500 Ns.

Learn more about impulse at: brainly.com/question/297527

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Sort the items based on whether they are simple machines or compound machines.
Tom [10]

Answer:

Simple machine: pair of tongs, seesaw and wheelbarrow

Compound machine: sewing machine, fishing rod and reel and crane.

Explanation:

Simple machine is the simplest device to use mechanical advantages. It has simplest mechanism to multiply the magnitude of force.

So, pair of tongs, seesaw and wheelbarrow are the example of simple machine because their mechanism is simplest.

Compound machine is a device that is made up of more than one simple machine.

so, sewing machine, fishing rod and reel and crane are example of compound machine because these devices shows more than one machine in it.

Thus, classification is as follows:

Simple machine: pair of tongs, seesaw and wheelbarrow

Compound machine: sewing machine, fishing rod and reel and crane.

3 0
4 years ago
Read 2 more answers
The frequency of a wave is 200 Hz. The wavelength is 0.1 m. What is the period of the wave?
Aleks04 [339]
The formula for the period of wave is: wave period is equals to 1 over the frequency.waveperiod=\frac{1}{frequency}
To get the value of period of wave you need to divide 1 by 200 Hz. However, beforehand, you have to convert 200 Hz to cycles per second. So that would be, 200 cyles per second or 200/s.
By then, you can start the computation by dividing 1 by 200/s. Since 200/s is in fractional form, you have to find its reciprocal form and multiply it to one which would give you 1 (one) second over 200. This would then lead us to the value 0.005 seconds as the wave period.

wave period= 1/200 Hz
Convert Hz to cycles per second first
200 Hz x 1/s= 200/second
Make 200/second as your divisor, so:

wave period= 1/ 200/s

get the reciprocal form of 200/s which is s/200

then you can start the actual computation:

wave period= 1 x s divided by 200

this would give us an answer of 0.005 s. 
6 0
3 years ago
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
Triss [41]

Answer:

2.1406 ×10^6 m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

now mass of electron =9.11×10^{-31}

so for electron

\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec

so the velocity of electron will be 2.1406×10^6 m/sec

4 0
3 years ago
A 25 kg mass is accelerated by a force at a rate of 5 m/s2. What is the magnitude of the force that accelerates the man?
svlad2 [7]
Force=mass*acceleration
F=ma
F=25*5
F=100 N
8 0
3 years ago
Acceleration always involves a change in
Scrat [10]
Velocity. Since velocity consists of a speed and a direction, acceleration is a change in speed, or direction, or both.
5 0
3 years ago
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