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11Alexandr11 [23.1K]
3 years ago
11

A 500kg car is driving through a neighborhood at 20m/s. Then the car hits a speed bump which causes it to slow to 15m/s. What wa

s the impulse delivered by the speed bump to the car?
Physics
1 answer:
lawyer [7]3 years ago
5 0

Based on the formula for calculating impulse, the impulse of the speed bump to the car is 2500 Ns.

<h3>What is the impulse of the speed bump?</h3>

  • Impulse = change in momentum
  • momentum = mass * velocity

Change in momentum = mu - mv

where u is initial velocity

v is final velocity

Impulse = 500 * 20  - 500 * 15

Impulse = 2500 Ns

Therefore, the impulse of the speed bump to the car is 2500 Ns.

Learn more about impulse at: brainly.com/question/297527

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Answer:

go ask a teacher

Explanation:

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7 0
3 years ago
An airplane is being pushed West by its engines with a force of 350 N as it starts to take off the runway at the Atlanta airport
Marizza181 [45]

Answer:

option C

Explanation:

given,

Force by the engine on plane in West direction = 350 N

Frictional force on the runway = 100 N in east

force exerted by the wind = 100 N in east

net force and direction = ?

consider west to be positive and east be negative.

when airplane will be moving there will be frictional as well as wind resistance will be acting in opposite direction of airplane

Net force = 350 N - 100 N - 100 N

                 = 150 N

as our answer comes out to be positive so the airplane will be moving in West

hence, the correct answer is option C

8 0
3 years ago
If a spring has a spring constant of 5 N/m and it is stretched 20 cm, what is the force of the Spring
Nastasia [14]

Answer:

1 N

Explanation:

First the equation is momentum = Force / distance

20 cm = 0.2 m

5 N/m = F / 0.2 m

F = 1 N

7 0
3 years ago
Identify the wave with the shortest wave length.
Valentin [98]

Answer:

d) gamma

Explanation:

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7 0
3 years ago
Read 2 more answers
a moving billiard ball collides with an identical stationary billiard ball in an elastic collision. after the collision, the sec
MArishka [77]

A billiard ball collides with a stationary identical billiard ball to make it move. If the collision is perfectly elastic, the first ball comes to rest after collision.

<h3>Why does the first ball comes to rest after collision ?</h3>

Let m be the mass of the two identical balls.  

u1 = velocity before the collision of ball 1

u2 = 0 = velocity of second ball that is at rest

v1 and v2 are the velocities of the balls after the collision.

From the conservation of momentum,

∴ mu1 + mu2 = mv1 + mv2

∴ mu1 = mv1 + mv2

∴ u1 = v1 + v2

In an elastic collision, the kinetic energy of the system before and after collision remains same.

\frac{1}{2}  mu_1^2+0=\frac{1}{2}  mv_1^2+\frac{1}{2}  mv_2^2

∴  \frac{1}{2}  m(v_1+v_2 )^2=\frac{1}{2} mv_1^2+\frac{1}{2}mv_2^2

∴ \frac{1}{2} mv_1^2+\frac{1}{2} mv_2^2+mv_1 v_2=\frac{1}{2}  mv_1^2+\frac{1}{2} mv_2^2

∴ mv₁v₂ = 0

  1. It is impossible for the mass to be zero.
  2. Because the second ball moves, velocity v2 cannot be zero.
  3. As a result, the velocity of the first ball, v1, is zero, indicating that it comes to rest after collision.
<h3>What is collision ?</h3>

An elastic collision is a collision between two bodies in which the total kinetic energy of the two bodies remains constant. There is no net transfer of kinetic energy into other forms such as heat, noise, or potential energy in an ideal, fully elastic collision.

Can learn more about elastic collision from brainly.com/question/12644900

#SPJ4

3 0
1 year ago
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