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Elenna [48]
3 years ago
13

how does the use of standard units of measurement solve problems in measurement regarding validity and reliabiility? explain it​

Physics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

Reliability can be estimated by comparing different versions of the same measurement. Validity is harder to assess, but it can be estimated by comparing the results to other relevant data or theory.

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Evaluate tan45/tan45
SIZIF [17.4K]

I'm not sure I completely understand the expression you want evaluated.

It looks like a fraction with the same exact thing in both the numerator and the denominator. A fraction like that always boils down to ' 1 '.

5 0
3 years ago
Read 2 more answers
1) Calculate the ideal efficiency of a heat engine that takes in energy at 800 K and expels heat to a
masha68 [24]

Answer:

Could you explain that more better?

Explanation:

3 0
3 years ago
A person is pulling their 20 kg luggage using the luggage handle. The handle is at an angle of 56 degrees above the horizontal.
rusak2 [61]

Answer:

The answer to your question is:  a = 1.99 m/s²

Explanation:

Data

mass = 20 kg

angle = 56°

Force = 71 N

horizontal acceleration = ?

Process

Find the horizontal force

                                           cos Ф = adjacent side / hypotenuse

                                          adjacent side = hypotenuse x cosФ

                                          adjacent side = 71 x cos 56

                                          a.s. = 39.70 N

Newton's second law

                                  F = ma

                                  a = F/m

                                 a = 39.7 / 20

                                  a = 1.99 m/s²

4 0
3 years ago
How much heat must be removed from 200 pounds of blanched vegetables at 189 degrees F to freeze them to a temperature of 22 degr
Virty [35]

To solve this problem it is necessary to apply the concepts related to heat exchange in the vegetable and water.

By definition the exchange of heat is given by

Q =mc\Delta T

where,

m = mass

c = specific heat

\Delta T = Change in temperature

Therefore the total heat exchange is given as

\Delta Q = Q_w+Q_v

\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)

Our values are given as,

Total mass is M_T = 200lb ,however the mass of solid vegetable and water is given as,

m_v= 0.4*200lb = 80lb

m_w=0.6*200lb=120lb

T_i = 183\°F\\T_f = 22\°F\\c_w = 1Btu/lbF\\c_v = 0.24Btu/lbF

Replacing at our equation we have,

\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)

\Delta Q = (120)(1)(183-22)+(80)(0.24)(183-22)

\Delta Q = 22411.2Btu

Therefore the heat removed is 22411.2 Btu

6 0
3 years ago
Coal is lifted out of a mine a vertical distance of 50 m by an engine that supplies 500 W to a conveyer belt. How much coal per
Brums [2.3K]

Answer:

mass = 61.16 kg

Explanation:

given data

distance = 50 m

energy = 500 W = 500 × 60sec = 30000 J/min

to find out

mass

solution

we will apply here energy equation  

that is

energy = m×g×h    .............1

put here all value m mass here and g = 9.81 and h is distance

energy = m×g×h

30000 = m×9.81×50

mass = 61.16 kg

7 0
3 years ago
Read 2 more answers
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