There the potential difference is -0. 553 keQ/R.
What is Electric potential ?
The amount of labor required to convey a unit of electric charge from a reference point to a given place in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential).
Electric potential at point 0,
V1 = ke Q/R
Electric potential at x= 2R
V2= keQ/ root5. R
Therefore potential difference is
dV = V2 - V1
Putting the values we get ,
dV = -0. 553 keQ/R
To learn more about electric potential click on the link below:
brainly.com/question/23980243
#SPJ4
Answer:
The relationship between amperage, voltage, and power is that power equals the amperage quantity times the amount of voltage.
Explanation: brainliest pls
Answer:
r = 2.93 m
Explanation:
mass of the person = 64.8 kg
speed v = 3.44 m/s
Force F = 261 N
using formula
the radius of the chamber is given by
r = 2.93 m
so, the radius of a chamber is equal to 2.93 m
Elastic potential energy is given by formula
here we know that
Now using above formula we have
So elastic potential energy in the chord is 14400 J
A)0.0714 a second (7*60)/(30*60)=4.284 4.284/60=0.0714
