A rock has a mass of 48 grams and a volume of 16 mL. What is the density of the rock?

-You wish to make a 0.203 M hydrochloric acid solution from a stock solution of 6.00 M hydrochloric acid. How much concentrated

lubasha [3.4K]

For all three questions, we will use the fact that

molarity = (moles of solute)/(liters of solution)

1) For 175 mL of solution at 0.203 M, this means that:

0.203 = (moles of solute)/0.175
moles of solute = 0.035523 mol

Considering the hydrochloric acid solution, if we have 0.035523 mol, then:

6.00 = 0.035523/(liters of solution)
liters of solution = 0.035523/6.00 = 0.0059205 = 5.92 mL (to 3 sf)

2) If there is 20.3 mL = 0.0203 L, then:

8.20 = (moles of solute)/0.0203
moles of solute = 0.16646 mol

This means that the molarity of the diluted solution is:

0.16646/(0.200) = 0.832 M (to 3 sf)

3) If we need 1.50 L of 0.700 M solution, then:

0.700 = (moles of solute)/1.50
moles of solute = 1.05 mol

Considering the 9.36 M acid solution, from which we need 1.05 mol of perchloric acid from,

9.36 = 1.05/(liters of solution)
liters of solution = 1.05/9.36, which is 0.11217948717949 L, or 112 mL (to 3 sf)

8 0

1 year ago

A mixture of krypton and argon gas is expanded from a volume of 88.0L to a volume of 100.0L, while the pressure is held constant

Firlakuza [10]

Answer:

-3.28 × 10⁴ J

Explanation:

Step 1: Given data

Pressure exerted (P): 27.0 atm

Initial volume (Vi): 88.0 L

Final volume (Vf): 100.0 L

Step 2: Calculate the work (w) done by the gaseous mixture

We will use the following expression.

w = -P × ΔV = -P × (Vf - Vi)

w = -27.0 atm × (100.0 L - 88.0 L)

w = -324 atm.L

Step 3: Convert w to Joule (SI unit)

We will use the conversion factor 1 atm.L = 101.325 J.

-324 atm.L × 101.325 J/1 atm.L = -3.28 × 10⁴ J

5 0

3 years ago

The volume of 2.050 M copper(II) nitrate that must be diluted with water to prepare 750.0 mL of a 0.8543 M solution is equal to

Lubov Fominskaja [6]

Answer:

.

Explanation:

´.

8 0

2 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

Answer: The mass of original oxalic acid sample is 6.75 grams

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

2 years ago

Type your answer in decimal form. Do not round. 7 days = hours

djyliett [7]

168.0
Hope this helps u

5 0

2 years ago

Read 2 more answers